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SPARQL 查询中同一列下的返回值

[英]Return values under same column in SPARQL query

给定三个可能的三元组对象, foaf:namefoaf:givenNamefoaf:familyName ,其中语句要么有foaf:name要么foaf:givenName + foaf:familyName ,例如:

<uri1> <foaf:name> "Lolly Loozles" .

<uri2> <foaf:givenName> "Stotly" .
<uri2> <foaf:familyName> "Styles" .

想知道如何编写一个 SPARQL 查询来返回一个新变量,比如pretty_name ,它要么是foaf:name的值,要么是来自foaf:givenNamefoaf:familyName的值的串联。

导致类似:

?o     | ?pretty_name
----------------------
<uri1> | Lolly Loozles
<uri2> | Stotly Styles

到目前为止,这是我所拥有的,但不确定如何进行:

PREFIX : <https://example.org/>
PREFIX foaf: <http://xmlns.com/foaf/0.1/>

# select two variables, not ideal...
SELECT ?foaf_fullName ?pretty_name

WHERE {    

    # Find all triples
    ?s ?p ?o .

    # Binds
    OPTIONAL { ?s foaf:name ?foaf_fullName }
    OPTIONAL { ?s foaf:givenName ?givenName }
    OPTIONAL { ?s foaf:familyName ?familyName }

    # Filter where predicate is part of list
    FILTER (?p IN (foaf:name, foaf:givenName, foaf:familyName ) )

    # Binds
    BIND( CONCAT(?givenName, ' ', ?familyName) AS ?pretty_name ) .

}

我曾想象并尝试添加另一个BIND以添加到?pretty_name ,但 SPARQL 引擎没有它:

BIND( ?foaf_fullName AS ?pretty_name ) .

我也很幸运地写了一个CONSTRUCT语句来获取我正在寻找的值,但没有能力写回这个三元组(出于多种原因):

CONSTRUCT { 
    ?s :hasPrettyName ?foaf_fullName .
    ?s :hasPrettyName ?pretty_name .
}

我原以为CONSTRUCT可以伴随SELECT ,但一定是错的?

任何见解或建议将不胜感激。

使用@StanislavKralin 评论/建议在没有IF子句的情况下使用COALESCE效果很好:

PREFIX : <https://example.org/>
PREFIX foaf: <http://xmlns.com/foaf/0.1/>

# select two variables, not ideal...
SELECT ?foaf_fullName ?pretty_name

WHERE {    

    # Find all triples
    ?s ?p ?o .

    # Binds
    OPTIONAL { ?s foaf:name ?foaf_fullName }
    OPTIONAL { ?s foaf:givenName ?givenName }
    OPTIONAL { ?s foaf:familyName ?familyName }

    # Filter where predicate is part of list
    FILTER (?p IN (foaf:name, foaf:givenName, foaf:familyName ) )

    # Binds
    BIND( COALESCE(?foaf_fullName, CONCAT(?givenName, ' ', ?familyName)) AS ?pretty_name )

}

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