使用多個條件選擇不同的值

Question

我試圖根據一個表的DISTINCT值向表中插入條目，這些表也不包含單獨表中的值。 我假設問題出在我的JOIN中。

在表wp_posts中，ID的值是唯一的，但在表wp_term_relationships中，object_id可以有多個條目。

我想要的是獲取描述中包含某些單詞的所有不同ID（在wp_posts中），但也沒有與該表中與object_id相關聯的wp_term_relationships表中的某些term_taxonomy_id

感謝您的回復，我做了一些更改，但仍然遇到問題。

//Here is what I have so far:
INSERT INTO wp_term_relationships (object_id, term_taxonomy_id, term_order) 
SELECT DISTINCT ID, '5209', '0' FROM wp_posts JOIN wp_term_relationships
ON wp_posts.ID = wp_term_relationships.object_id
WHERE wp_posts.post_content LIKE '%Cadillac%'
AND wp_posts.post_content LIKE '%Escalade%'
AND wp_term_relationships.term_taxonomy_id not like '5209';

生成的查詢嘗試插入不符合最后條件的值。 我假設問題在於加入。

答案后編輯：

感謝Gen Wan建議的代碼，引導我回答我的問題！ 這是正確的代碼：

INSERT INTO wp_term_relationships (object_id, term_taxonomy_id, term_order) 
SELECT DISTINCT ID, '5209', '0' FROM wp_posts 
JOIN (
    select object_id, term_taxonomy_id from wp_term_relationships
    WHERE wp_term_relationships.term_taxonomy_id = 5209
)a
ON wp_posts.ID = a.object_id
WHERE wp_posts.post_content LIKE '%Cadillac%'
AND wp_posts.post_content LIKE '%Escalade%'
AND a.term_taxonomy_id not like '5209';

Answer 1

這將工作：

INSERT INTO wp_term_relationships (object_id, term_taxonomy_id, term_order) 
SELECT DISTINCT ID, '5209', '0' FROM wp_posts JOIN wp_term_relationships
ON wp_posts.ID = wp_term_relationships.object_id
WHERE wp_posts.post_content LIKE '%Cadillac%'
AND wp_posts.post_content LIKE '%Escalade%'
AND  wp_term_relationships.term_taxonomy_id not like  '5209';

Answer 2

不確定您正在使用哪個數據庫服務器，但嘗試更改您的最后條件：

AND NOT wp_term_relationships.wp_term_relationships = '5209';

至：

AND wp_term_relationships.wp_term_relationships <> '5209';

Answer 3

如果我正確理解您的問題，您需要首先從wp_term_relationships獲取不同的object_id和term_taxonomy_id：

select distinct object_id, term_taxonomy_id from wp_term_relationships

然后使用您的條件加入派生表：

INSERT INTO wp_term_relationships (object_id, term_taxonomy_id, term_order) 
SELECT DISTINCT ID, '5209', '0' FROM wp_posts 
JOIN (select distinct object_id, term_taxonomy_id from wp_term_relationships)a
ON wp_posts.ID = a.object_id
WHERE wp_posts.post_content LIKE '%Cadillac%'
AND wp_posts.post_content LIKE '%Escalade%'
AND a.term_taxonomy_id not like '5209';

Answer 4

您在選擇中硬編碼了分類法id = 5209。 這就是為什么你的插入將5209放在所有插入的行中。

 SELECT DISTINCT ID, **'5209'**, '0'  

請向我們展示樣本數據，以便我們可以清楚地看到問題。 我去了這個免費網站創建一個數據庫沙箱： https ： //www.db-fiddle.com/
然后我運行你的查詢，我沒有看到結果的問題。 如果您有不同的預期結果，請向我們展示。

謝謝。

網站： https ： //www.db-fiddle.com/復制並粘貼此並執行：

架構：

create table wp_posts(ID integer, post_content varchar);
insert into wp_posts values (1,   'Cadillac Escalade');
insert into wp_posts values (2,   'Ford Escape');
insert into wp_posts values (3,   'Cadillac Escalade');
insert into wp_posts values (4,   'Escalade Cadillac');
insert into wp_posts values (5,   'Escalade Cadillac');
create table wp_term_relationships(object_id integer, term_taxonomy_id integer); 
insert into wp_term_relationships values (1            ,5209);
insert into wp_term_relationships values (1            ,1000);
insert into wp_term_relationships values (2            ,5209);
insert into wp_term_relationships values (2            ,1000 );
insert into wp_term_relationships values (2            ,5209);
insert into wp_term_relationships values (3            ,1000);
insert into wp_term_relationships values (5            ,5209);
insert into wp_term_relationships values (5            ,1000);

查詢：

SELECT DISTINCT ID, term_taxonomy_id, '5209' as new_term_taxonomy_id, '0' as nothing_ 
FROM wp_posts 
JOIN wp_term_relationships
ON wp_posts.ID = wp_term_relationships.object_id
WHERE wp_posts.post_content LIKE '%Cadillac%'
AND wp_posts.post_content LIKE '%Escalade%'
AND wp_term_relationships.term_taxonomy_id <> 5209;