[英]how to serialize a property property only not the whole property using xml attributes?
我想序列化一個包含屬性的對象,而這些屬性之一我只想序列化其名稱。
如何不使用IXmlSerializable
接口而僅使用屬性來執行此操作。
[Serializable]
public class Class
{
public Class()
{
}
[XmlAttribute]
public string ClassId{get;set;}
[XmlAttribute]
public Teacher Teacher{get;set;}
[XmlArray("Students")]
[XmlArrayItem("Student", Type=typeof(Student))]
public List<Student> Students { get; } = new List<Student>();
}
[Serializable]
public class Student
{
public Student()
{
}
public Class CurrentClass{get;set;}
[XmlAttribute]
public string Name { get; set; } = "New Student";
[XmlAttribute]
public int Age { get; set; } = 10;
}
CurrentClass
這個屬性我不想忽略它。
我只想序列化其CurrentClass.ClassId
值。
如果您僅查找要與Student對象一起序列化的ClassId,則僅具有ClassId屬性而不是整個Class對象更為有意義。
public class GenerateXml
{
public static void Create()
{
Class c = new Class();
c.Teacher = new Teacher() {Name = "Mr. Henry"};
var s = new Student() { Age = 14, Name = "Suzy", Teacher = c.Teacher };
c.Students.Add(s);
s = new Student() {Age = 13, Name = "Adam", Teacher = c.Teacher};
c.Students.Add(s);
var serializer = new XmlSerializer(c.GetType());
XmlTextWriter writer = new XmlTextWriter("class.xml", Encoding.ASCII);
writer.Formatting = Formatting.Indented;
writer.Indentation = 4;
serializer.Serialize(writer, c);
}
}
[Serializable]
public class Class
{
public Class()
{
}
[XmlAttribute]
public string ClassId { get; set; }
[XmlElement]
public Teacher Teacher { get; set; }
[XmlArray("Students")]
[XmlArrayItem("Student", Type = typeof(Student))]
public List<Student> Students { get; } = new List<Student>();
}
[Serializable]
public class Student
{
public Student()
{
}
[XmlElement]
public Teacher Teacher { get; set; }
[XmlAttribute]
public string ClassId { get; set; }
[XmlAttribute]
public string Name { get; set; } = "New Student";
[XmlAttribute]
public int Age { get; set; } = 10;
}
[Serializable]
public class Teacher
{
public Teacher()
{
}
[XmlAttribute]
public string Name { get; set; } = "New Teacher";
[XmlAttribute]
public int Age { get; set; } = 30;
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.