程序保持循環無限的功能？

Question

目前正致力於基礎蟒蛇課的Rock Paper Scissors游戲。 在過去的一周里，我一直在研究它，因為我抬頭看了如何制作一個基本的python游戲，偶然發現了一篇文章並且離開了它。 不知道為什么，但它不斷循環。 我想保持結構與此類似，因為我的導師讓我保持這樣。

我已經嘗試更改cpu_rand和cpu_choice，並將函數results（）放在不同的位置，但也無法正常工作。

import random #import random module
import sys #import system module
def playgame():
    while True:
        player_choice = input("Rock, Paper, or Scissors?")
        cpu_rand = random.randint(1,3) #Generate random integer 1-3
        cpu_choice = None
        if cpu_rand == 1: #if cpu_choice = 1, cpu_choice = "Rock"
            cpu_choice = "Rock"
        elif cpu_rand == 2: #if cpu_choice = 2, cpu_choice = "Scissors"
            cpu_choice = "Scissors"
        elif cpu_rand == 3: #if cpu_choice = 3, cpu_choice = "Paper"
            cpu_choice = "Paper"
def results(): #check results of player choice v computer choice
    play_again = None #Sets this to null for future reference, for asking if playing again.
    if(player_choice == cpu_choice):    #Tie
        print("It's a Tie")
        play_again = input("Retry?")
    #Rock Outcomes
    elif(player_choice == "Rock" and cpu_choice == "Scissors"):
        print("You Win!")
        play_again = input("Play again?")
    elif(player_choice == "Rock" and cpu_choice == "Paper"):
        print("You Lose!")
        play_again = input("Play again?")
    #Paper Outcomes
    elif(player_choice == "Paper" and cpu_choice == "Scissors"):
        print("You Lose!")
        play_again = input("Play again?cpu")
    elif(player_choice == "Paper" and cpu_choice == "Rock"):
        print("You Win!")
        play_again = input("Play again?")
    #Scissors Outcomes
    elif(player_choice == "Scissors" and cpu_choice == "Rock"):
        print("You Lose!")
        play_again = input("Play again?")
    elif(player_choice == "Scissors" and cpu_choice == "Paper"):
        print("You Win!")
        play_again = input("Play again?")

    if play_again == "Yes": #if elif play again statements, from if/elif statements, play_again is changed to an input
        playgame()
    elif play_again == "No":
        print("You Lose!")
        sys.exit()
    else:
        print("Invalid Command")
        play_again = input("play again?")
        return play_again
    results()

def start():
    while True:
        gamestart = input("You ready to play some Rock, Paper, Scissors? (y/n)")
        if gamestart == "y":
                playgame()
                return gamestart
        elif gamestart == "n":
            print("Game Over!")
            break
        else:
            print("Invalid Command")
start()

我希望返回的結果是結果函數下的所有內容，因此如果player_choice == cpu_choice，那么它將打印出其下的內容。 相反，它會回到“搖滾，紙張或剪刀？”

Answer 1

您從未在代碼中調用結果函數，因此它從未運行過。

Answer 2

你沒有調用results() 。 而且player_choice和cpu_choice是playgame()中的局部變量。

import random #import random module
import sys #import system module
def playgame():
    while True:
        player_choice = input("Rock, Paper, or Scissors?")
        cpu_rand = random.randint(1,3) #Generate random integer 1-3
        cpu_choice = None
        if cpu_rand == 1: #if cpu_choice = 1, cpu_choice = "Rock"
            cpu_choice = "Rock"
        elif cpu_rand == 2: #if cpu_choice = 2, cpu_choice = "Scissors"
            cpu_choice = "Scissors"
        elif cpu_rand == 3: #if cpu_choice = 3, cpu_choice = "Paper"
            cpu_choice = "Paper"
        results(player_choice, cpu_choice)
def results(player_choice, cpu_choice): #check results of player choice v computer choice
    play_again = None #Sets this to null for future reference, for asking if playing again.
    if(player_choice == cpu_choice):    #Tie
        print("It's a Tie")
        play_again = input("Retry?")
    #Rock Outcomes
    elif(player_choice == "Rock" and cpu_choice == "Scissors"):
        print("You Win!")
        play_again = input("Play again?")
    elif(player_choice == "Rock" and cpu_choice == "Paper"):
        print("You Lose!")
        play_again = input("Play again?")
    #Paper Outcomes
    elif(player_choice == "Paper" and cpu_choice == "Scissors"):
        print("You Lose!")
        play_again = input("Play again?cpu")
    elif(player_choice == "Paper" and cpu_choice == "Rock"):
        print("You Win!")
        play_again = input("Play again?")
    #Scissors Outcomes
    elif(player_choice == "Scissors" and cpu_choice == "Rock"):
        print("You Lose!")
        play_again = input("Play again?")
    elif(player_choice == "Scissors" and cpu_choice == "Paper"):
        print("You Win!")
        play_again = input("Play again?")

    if play_again == "Yes": #if elif play again statements, from if/elif statements, play_again is changed to an input
        playgame()
    elif play_again == "No":
        print("You Lose!")
        sys.exit()
    else:
        print("Invalid Command")
        play_again = input("play again?")
        return play_again
    results()

def start():
    while True:
        gamestart = input("You ready to play some Rock, Paper, Scissors? (y/n)")
        if gamestart == "y":
                playgame()
                return gamestart
        elif gamestart == "n":
            print("Game Over!")
            break
        else:
            print("Invalid Command")
start()

Answer 3

你的代碼是如此密集和重復，我可以建議另一種方法嗎？：

import random
wins = [
    ('paper', 'rock'),   # paper wins over rock
    ('rock', 'scissors'),
    ('scissors', 'paper'),
]
items = ['rock', 'paper', 'scissors']

def computer_choice():
    return random.choice(items)

def player_choice():
    for i, item in enumerate(items):
        print i, item
    while 1:
        choice = input("choose [0..%d]: " % (len(items)-1))
        if 0 <= choice < len(items):
            break
    return items[choice]

while 1:
    cpu = computer_choice()
    human = player_choice()
    print "CPU: %s, HUMAN: %s" % (cpu, human)
    if cpu == human:
        print 'tie..'
    elif (cpu, human) in wins:
        print "CPU wins."
    else:
        print "HUMAN wins."
    again = raw_input("play again? [q to quit]: ")
    print
    if again.lower() == 'q':
        break

樣本會話：

0 rock
1 paper
2 scissors
choose [0..2]: 0
CPU: scissors, HUMAN: rock
HUMAN wins.
play again? [q to quit]:

0 rock
1 paper
2 scissors
choose [0..2]: 1
CPU: paper, HUMAN: paper
tie..
play again? [q to quit]:

0 rock
1 paper
2 scissors
choose [0..2]: 1
CPU: scissors, HUMAN: paper
CPU wins.
play again? [q to quit]:

使這個玩搖滾，紙，剪刀，蜥蜴，spock（ https://bigbangtheory.fandom.com/wiki/Rock,_Paper,_Scissors,_Lizard,_Spock ）的唯一變化是：

wins = [
    ('scissor', 'paper'),    # Scissors cuts Paper 
    ('paper', 'rock'),       # Paper covers Rock 
    ('rock', 'lizard'),      # Rock crushes Lizard 
    ('lizard', 'spock'),     # Lizard poisons Spock 
    ('spock', 'scissors'),   # Spock smashes Scissors
    ('scissors', 'lizard'),  # Scissors decapitates Lizard
    ('lizard', 'paper'),     # Lizard eats Paper
    ('paper', 'spock'),      # Paper disproves Spock
    ('spock', 'rock'),       # Spock vaporizes Rock
    ('rock', 'scissors'),    # (and as it always has) Rock crushes Scissors 
]
items = ['rock', 'paper', 'scissors', 'lizard', 'spock']

樣品運行

0 rock
1 paper
2 scissors
3 lizard
4 spock
choose [0..4]: 4
CPU: scissors, HUMAN: spock
HUMAN wins.
play again? [q to quit]:

0 rock
1 paper
2 scissors
3 lizard
4 spock
choose [0..4]: 2
CPU: spock, HUMAN: scissors
CPU wins.
play again? [q to quit]: