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[英]How I do the equivalent of this curl command using Spring's RestTemplate?
[英]Convert curl command into RestTemplate
我有以下curl表達式:
curl --data 'api_key=API_Key' --data-urlencode 'event=[{"user_id":"12345", "event_type":"buy_song"}]' https://someapi
應該轉換為RestTemplate.postForEntity調用。 我這樣做轉換:
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_FORM_URLENCODED);
MultiValueMap<String, String> params = new LinkedMultiValueMap<>();
params.add("api_key", "API_Key");
params.add("event", URLEncoder.encode(objectMapper.writeValueAsString(Collections.singletonList(e)), "UTF-8"));
// send
HttpEntity<MultiValueMap<String, String>> request = new HttpEntity<>(params, headers);
ResponseEntity<String> response = restTemplate.postForEntity("https://someapi", request, String.class);
服務器返回400 Bad請求
我確認Jackson的objectmapper正確序列化了對象objectMapper.writeValueAsString(Collections.singletonList(e))
我懷疑我無法正確處理--data-urlencode
示例curl的--data
和--data-urlencode
的混合。
你能告訴我我做錯了什么嗎?
// org.apache.commons.collections.map.HashedMap
HashedMap requestBody = new HashedMap();
requestBody.put("api_key", "API_Key");
requestBody.put("event", URLEncoder.encode(objectMapper.writeValueAsString(Collections.singletonList(e)), "UTF-8"));
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_FORM_URLENCODED);
String jsonBody = new ObjectMapper().writeValueAsString(requestBody);
HttpEntity<String> entity = new HttpEntity<>(jsonBody, headers);
ResponseEntity<String> response = restTemplate.postForEntity("https://someapi", entity, String.class);
對我來說很好:
這是帶有客戶端和請求的代碼,請忽略請求簽名
curl -X GET \
http://localhost:8080/article/so \
-H 'cache-control: no-cache' \
-d 'api_key=API_Key&event=%5B%7B%22user_id%22%3A%2212345%22%2C%20%22event_type%22%3A%22buy_song%22%7D%5D'
controller:第一個請求會觸發你的代碼:
// This is just to trigger, you can ignore it.
@RequestMapping(value = "/article/so", method = RequestMethod.GET)
public void addArticle1() throws UnsupportedEncodingException, JsonProcessingException {
articleServiceImpl.test();
}
上面的請求將轉到服務層,其中代碼與您的代碼相同。
public void test() throws JsonProcessingException, UnsupportedEncodingException {
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_FORM_URLENCODED);
MultiValueMap<String, String> params = new LinkedMultiValueMap<>();
Event e = new Event();
e.setEvent_type("buy_song");
e.setUser_id("12345");
params.add("api_key", "API_Key");
String encode = URLEncoder.encode(objectMapper.writeValueAsString(Collections.singletonList(e)), "UTF-8");
params.add("event", encode);
HttpEntity<MultiValueMap<String, String>> request = new HttpEntity<>(params, headers);
ResponseEntity<String> response = restTemplate.postForEntity("http://localhost:8080/article/so", request, String.class);
System.out.println(response);//<200,[Content-Length:"0", Date:"Fri, 31 May 2019 09:26:24 GMT"]>
}
然后再次控制器,只是檢查控制器是否接受來自調用者的String對象或Event對象。 這里Event作為URLEncodedString傳遞,我在這里作為輸出。
@RequestMapping(value = "/article/so", method = RequestMethod.POST, consumes = MediaType.APPLICATION_FORM_URLENCODED_VALUE)
public void addArticle2(@RequestParam String api_key,@RequestParam String event) {
System.out.println(api_key); // API_Key
System.out.println(event); // %5B%7B%22user_id%22%3A%2212345%22%2C%22event_type%22%3A%22buy_song%22%7D%5D
}
我認為唯一的問題是MediaType
,您發送的數據不是表單數據( APPLICATION_FORM_URLENCODED
)
這是json數據,所以你需要使用MediaType.APPLICATION_JSON
東西
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
// converting form variable to Map
MultiValueMap<String, String> map= new LinkedMultiValueMap<>();
map.add("api_key", "API_Key");
map.add("event", URLEncoder.encode(objectMapper.writeValueAsString(Collections.singletonList(e)), "UTF-8"));
// finally build Request
HttpEntity<MultiValueMap<String, String>> request = new HttpEntity<>(map, headers);
ResponseEntity<String> response = restTemplate.postForEntity(
apiUrl, request , String.class);
請參閱本關於RestTemplate詳細
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