[英]Iterate over an array and add values to second array based on condition
我必須將值從一個數組傳遞到另一個數組,條件是名稱以“A”開頭。
var favorites = [] var famous = [ 'alex smith', 'amy whinehouse', 'cameron diaz', 'brad pitt', 'ashton kutcher', 'mark whalberg', 'morgan freeman', 'mila kunis'] for (var i=0; i<famous.length; i++ ) { if(famous[i][0]==="a") { favorites.push((famous[i][0]).unshift()) } }
控制台返回一個錯誤。
使用 ES6 你可以這樣寫:
var famous = ['alex smith', 'amy whinehouse', 'cameron diaz', 'brad pitt', 'ashton kutcher', 'mark whalberg', 'morgan freeman', 'mila kunis'] var favorites = famous.filter(artist => artist[0] == 'a'); console.log(favorites)
您的原始代碼應如下所示:
var favorites = [] var famous = ['alex smith', 'amy whinehouse', 'cameron diaz', 'brad pitt', 'ashton kutcher', 'mark whalberg', 'morgan freeman', 'mila kunis'] for (var i=0; i<famous.length; i++) { if (famous[i][0]==='a') { favorites.push(famous[i]); } } console.log(favorites)
您的錯誤代碼TypeError: famous[i][0].unshift is not a function
表示您試圖在不是數組的東西上使用數組函數。 您在字符串上調用函數unshift
但對於字符串,該函數根本不存在。
您可以使用過濾方法
var favorites = []; var famous = [ 'alex smith', 'amy whinehouse', 'cameron diaz', 'brad pitt', 'ashton kutcher', 'mark whalberg', 'morgan freeman', 'mila kunis']; var favorites = famous.filter((artist, index) => { if (artist[0] == 'a') { delete famous[index]; return true } return false; }); famous = famous.filter(Boolean) console.log(famous) console.log(favorites)
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