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[英]C# Convert List<string> to Dictionary<string, string> LINQ
[英]Convert List of Dictionary<string, List> into list C# Linq
這是我的源類型=> IEnumerable<IDictionary<string, IEnumerable<string>>>
這是我的目標類型=> IEnumerable<string>
字符串清單
[ "ca:aws_client:firstElementIntheList]", "ca:aws_client:secondElementInTheList]" ]
字符串清單
[ "ca:aws_client:System.Linq.Enumerable+SelectListIterator`2[System.String,System.String]", "ca:aws_client:System.Linq.Enumerable+SelectListIterator`2[System.String,System.String]" ]
input
.ToList()
.SelectMany(d => d)
.Select(i => $"ca:{i.Key}:{i.Value.Select(l => l)}")
.ToList()
您正在尋找在SelectMany
使用結果選擇器,而不是第二個select語句。
您可能想要這樣的東西:
var dict = new Dictionary<string, IEnumerable<string>>
{
{"one", new List<string> {"1","2","3"}},
{"two", new List<string> {"1","2","3"}}
};
var res = dict.SelectMany(d => d.Value, (a, b) => $"ca:{a.Key}:{b}");
foreach(var val in res)
Console.WriteLine(val);
/* output:
ca:one:1
ca:one:2
ca:one:3
ca:two:1
ca:two:2
ca:two:3
*/
編輯:
我注意到您實際上正在使用詞典列表。 解決方案基本相同,但具有更多SelectMany
。
var list = new List<Dictionary<string, IEnumerable<string>>>
{
new Dictionary<string, IEnumerable<string>> {
{"one", new List<string> {"1","2","3"}},
{"two", new List<string> {"1","2","3"}}
},
new Dictionary<string, IEnumerable<string>> {
{"three", new List<string> {"1","2","3"}},
{"four", new List<string> {"1","2","3"}}
}
};
var res = list.SelectMany(x => x)
.SelectMany(d => d.Value, (a, b) => $"ca:{a.Key}:{b}");
foreach(var val in res)
Console.WriteLine(val);
如果有人可以提出一種干凈的方法來處理SelectMany的多種方法,而不是將它們堆疊在一起,那么我想了解一下自己的觀點。
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