[英]python: How to delete every character after a specific character in a string?
我必須通過刪除'U'之后的每個字符來過濾字符串變量。
例如:
1)具有075600U2
我應該得到075600U
2)具有892009U24
我應該得到892009U
我試圖做一個for循環,將U之后的每個字符替換為”,但沒有得到任何結果
material = '075600U2'
for i in range((material.find('U')+1), len(material)):
material[i].replace('')
print(material)
我希望輸出為“ 075600U”,但實際輸出為“ 075600U2”
任何想法?
In [34]: material = '075600U2'
In [35]: ''.join(material.partition("U")[:2])
Out[35]: '075600U'
In [36]: material = '075600U258'
In [37]: ''.join(material.partition("U")[:2])
Out[37]: '075600U'
In [38]: material = '075600'
In [39]: ''.join(material.partition("U")[:2])
Out[39]: '075600'
re.sub
函數在這里很方便:
material = '075600U2'
output = re.sub(r'(?<=U).*', '', material)
print(output)
打印:
075600U
與其替換這些字符,不如將它們切成薄片?
material = material[:material.find('U')+1]
import re
replaced = re.sub('U[\d]*', 'U', material)
print(replaced)
輸出
075600U
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