python: How to delete every character after a specific character in a string?

Question

I have to filter a string variable by removing every character after 'U'.

For example:

1) having 075600U2

I should get 075600U

2) having 892009U24

I should get 892009U

I tried to do a for loop to replace every character after U as '' but I'm not getting any result

    material = '075600U2'

    for i in range((material.find('U')+1), len(material)):
        material[i].replace('')

    print(material)

I expect the output of '075600U', but the actual output is '075600U2'

Any idea?

Answer 1

In [34]: material = '075600U2'                                                                                                                                                                                                                                                                                                

In [35]: ''.join(material.partition("U")[:2])                                                                                                                                                                                                                                                                                 
Out[35]: '075600U'

In [36]: material = '075600U258'                                                                                                                                                                                                                                                                                              

In [37]: ''.join(material.partition("U")[:2])                                                                                                                                                                                                                                                                                 
Out[37]: '075600U'

In [38]: material = '075600'                                                                                                                                                                                                                                                                                                  

In [39]: ''.join(material.partition("U")[:2])                                                                                                                                                                                                                                                                                 
Out[39]: '075600'

Answer 2

The re.sub function comes in handy here:

material = '075600U2'
output = re.sub(r'(?<=U).*', '', material)
print(output)

This prints:

075600U

Answer 3

与其替换这些字符，不如将它们切成薄片？

material = material[:material.find('U')+1]

Answer 4

import re 
replaced = re.sub('U[\d]*', 'U', material) 
print(replaced)

output

075600U

https://docs.python.org/3/library/re.html