如何返回具有動態字段的對象

Question

我需要在一年中的每個月為每個商店創建一個折線圖。 但是，商店是動態的，它取決於商家。 這是來自數據庫的返回查詢：

[{"Month":"January","Total":44,"Store":"Refoil"},
{"Month":"January","Total":242,"Store":"Sustainable Salons"},
{"Month":"January","Total":99,"Store":"The Base Collective"},
{"Month":"February","Total":37,"Store":"Refoil"},
{"Month":"February","Total":219,"Store":"Sustainable Salons"},
{"Month":"February","Total":122,"Store":"The Base Collective"},
{"Month":"February","Total":148,"Store":"Watersco Australia"}]

我怎樣才能返回這樣的對象：

[{"Month":"January","Refoil":44,"Sustainable Salons":242},

{"Month":"February","Refoil":2,"Sustainable Salons":10}]

Answer 1

您可以使用ExpandoObject轉置結果：-

var results = new List<Result>();

results.Add(new Result() { Month = "January", Total = 44, Store = "Refoil" });
results.Add(new Result() { Month = "January", Total = 242, Store = "Sustainable Salons" });
results.Add(new Result() { Month = "January", Total = 99, Store = "The Base Collective" });
results.Add(new Result() { Month = "February", Total = 37, Store = "Refoil" });
results.Add(new Result() { Month = "February", Total = 219, Store = "Sustainable Salons" });
results.Add(new Result() { Month = "February", Total = 122, Store = "The Base Collective" });
results.Add(new Result() { Month = "February", Total = 148, Store = "Watersco Australia" });

var transpose = results.GroupBy(x => x.Month).Select(x =>
{
    dynamic e = new ExpandoObject();

    e.Month = x.Key;

    var ed = e as IDictionary<string, object>;

    x.ToList().ForEach(y => ed.Add(y.Store, y.Total));

    return e;
});

Debug.WriteLine(JsonConvert.SerializeObject(transpose, Newtonsoft.Json.Formatting.Indented));

Result類：-

public class Result
{
    public string Month { get; set; }
    public string Store { get; set; }
    public int Total { get; set; }
}

給出以下輸出：-

[
  {
    "Month": "January",
    "Refoil": 44,
    "Sustainable Salons": 242,
    "The Base Collective": 99
  },
  {
    "Month": "February",
    "Refoil": 37,
    "Sustainable Salons": 219,
    "The Base Collective": 122,
    "Watersco Australia": 148
  }
]

Answer 2

1. Deserialize your json to c# object 參考Deserializing JSON data to C# using JSON.NET

2. 使用 linq 和 json 按月分組序列化您的 c# 對象並將其發送到您的客戶端..

如果這沒有幫助，請提供更多詳細信息，按月對數據進行分組后您會期望什么？。

Answer 3

將 db 響應映射到 C# 模型，然后創建具有所需結構的匿名對象並使用 Json.Net 進行序列化。 如果這不是您想要的結果，請添加更多詳細信息