[英]How to filter List<T> and find average to make a distinct List<T>
如何通過特定字段將列表過濾為不同的值,而值不同的地方取其平均值。 請看例子
{
Public int Time;
Public float Voltage;
Public float Current;
Public Resistance(int time, float voltage, float current)
{
Time = time;
Voltage = voltage;
Current = current;
}
Public List<Resistance> _resistances = new List<Resistance>();
_resistances.Add(new Resistance(Time = 1, Voltage =3.2, Current = 1);
_resistances.Add(new Resistance(Time = 1, Voltage =4.0, Current = 2);
_resistances.Add(new Resistance(Time = 1, Voltage =6.5, Current = 6);
_resistances.Add(new Resistance(Time = 2, Voltage =3.2, Current =4);
_resistances.Add(new Resistance(Time =2, Voltage =3.2, Current = 2);
_resistances.Add(new Resistance(Time = 3, Voltage 5, Current = 1);
目的是列出以下內容:
_resistance[0]{ Time =1,, Voltage = Average(3.2,4,6.5), Current = Average(1,2,6))
_resistance[1]{ Time =2,, Voltage = Average(3.2,3.2,5), Current = Average(4,2,1))
}
對於任何任意值和條目數量
我嘗試了以下
int divisor = 1;
double voltageSum = 0;
double currentSum = 0;
while (j >= 1)
{
while (_resistances[j].Time== _resistances[j - 1].Time)
{
divisor++;
voltageSum += _resistances[j].Voltage;
currrentSum += _resistances[j].Current;
_resistances.RemoveAt(j);
j -= 1;
}
var averageVoltage = voltageSum / divisor;
var averageCurrent = currentSum / divisor;
_rawDataList[j].Voltage = (float)averageVoltage;
_rawDataList[j].Current= (float)averageCurrent;
j -= 1;
}
我知道這是錯誤的,但是我似乎無法弄清楚修改列表的邏輯,我認為創建新列表並在forloop中追加也許是前進的方向,但我無法解決。 我認為Linq可能會有所幫助,但對Lambda表達式的了解不是太豐富。 提前致謝
您可以使用Linq完成此操作,將記錄按時間分組,然后使用“ Average
功能為時間組計算“電壓”和“電流”的值:
_resistances
.GroupBy(r => r.Time)
.Select(g => new {
Time = g.Key,
Voltage = g.Average(r => r.Voltage),
Current = g.Average(r => r.Current)
});
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.