[英]How do I completely bootstrap a grails environment?
我有包含的grails腳本,可以在Internet上的某個隨機位置找到它,它對於在自舉的grails env中啟動腳本非常有效。 似乎唯一沒有做的就是像運行run-app一樣啟動conf/*Bootstrap.groovy
腳本。
是否有另一個功能如loadApp()
和configureApp()
可以為我完成此工作?
import org.codehaus.groovy.grails.support.PersistenceContextInterceptor
Ant.property(environment: "env")
grailsHome = Ant.antProject.properties."env.GRAILS_HOME"
includeTargets << new File("${grailsHome}/scripts/Bootstrap.groovy")
target('default': "Runs scripts in the test/local directory") {
if (!args) { throw new RuntimeException("[fail] This script requires an argument - the script to run.") }
depends(configureProxy, packageApp, classpath)
classLoader = new URLClassLoader([classesDir.toURI().toURL()] as URL[], rootLoader)
Thread.currentThread().setContextClassLoader(classLoader)
loadApp()
configureApp()
def interceptor = null
def beanNames = appCtx.getBeanNamesForType(PersistenceContextInterceptor)
if (beanNames && beanNames.size() == 1) {
interceptor = appCtx.getBean(beanNames[0])
}
try {
interceptor?.init()
new GroovyScriptEngine(Ant.antProject.properties."base.dir", classLoader).run("scripts/${args}.groovy", new Binding(['appCtx':appCtx]))
interceptor?.flush()
} catch (Exception e) {
e.printStackTrace()
interceptor?.clear()
} finally {
interceptor?.destroy()
}
}
是的,嘗試
新的BootStrap()。init()
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