在SpringBoot客戶端中使用WebServiceTemplate進行SOAP Web服務調用

Question

我正在使用WebServiceTemplate調用SOAP Web服務。 我可以使用SOAP UI通過以下輸入來調用服務，並獲得正確的響應。

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:abc="http://abc.hs.com/">
      <soapenv:Header>
                <version>1<version>
   </soapenv:Header>
   <soapenv:Body>
      <abc:getUser>
         <userId>pan</userId>
      </abc:getUser>
   </soapenv:Body>
</soapenv:Envelope>

但是，當使用WebserviceTemplate進行調用時，如下所示：

public String getUser(String userId) {
        List<String> detail = new ArrayList<String>();
        try {
            template = new WebServiceTemplate(marshaller);
            String requestPayload = getXmlInput();// This is same xml I am sending using SOAPUI 
            StreamSource source = new StreamSource(new StringReader(requestPayload));
            StreamResult result = new StreamResult(System.out);
            template.sendSourceAndReceiveToResult("http://localhost:8080/HERSvc/InsService", source,
                    new WebServiceMessageCallback() {
                        public void doWithMessage(WebServiceMessage message) throws IOException {
                        TransportContext context = TransportContextHolder.getTransportContext();
                        HttpUrlConnection connection = (HttpUrlConnection) context.getConnection();
                        connection.addRequestHeader("Content-Type", "text/xml; charset=utf-8");
                        connection.addRequestHeader("soapAction", "");
                }
            },result);
        } catch (IOException e) {
            e.printStackTrace();
        }
        return "";
    }

我在服務器端收到以下錯誤： E org.apache.axis2.engine.AxisEngine receive The endpoint reference (EPR) for the Operation not found is http://localhost:8080/HERSvc/InsService and the WSA Action = . If this EPR was previously reachable, please contact the server administrator. E org.apache.axis2.engine.AxisEngine receive The endpoint reference (EPR) for the Operation not found is http://localhost:8080/HERSvc/InsService and the WSA Action = . If this EPR was previously reachable, please contact the server administrator.

客戶端錯誤消息：發生意外錯誤（類型=內部服務器錯誤，狀態= 500）。

經過https://stackoverflow.com/questions/5981379/the-endpoint-reference-epr-for-the-operation-not-found-is之后，我在標頭中添加了Content-Type和soapAction

注意：我懷疑問題是我的requestPayload格式不正確。 它與SOAP UI中使用的字符串相同。 似乎輸入已轉換為Body

<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
<SOAP-ENV:Header/>
<SOAP-ENV:Body>
<soapenv:Envelope xmlns:abc="http://abc.hs.com/" xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
    <soapenv:Header>
    <version>1<version>
</soapenv:Header>
    <soapenv:Body>
        <abc:getUser>
            <userId>pan</userId>
        </abc:getUser>
    </soapenv:Body>
</soapenv:Envelope>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope> 

Answer 1

問題是所需的標題格式不正確。 最初，我無法創建objectPayload，因此無法使用marshalSendAndReceive。 因此，為了創建適當的objectPayload，我使用wsdl從命令提示符下生成ObjectFactory，然后將所有創建的對象導入到項目中。 使用marshalSendAndReceive如下

wsimport -d generated http://example.org/stock?wsdl

public User getUser(User user) {
        try {
            template = new WebServiceTemplate(marshaller);
            JAXBElement<?> response =  (JAXBElement<?>)template.marshalSendAndReceive("http://localhost:8080/HERSvc/InsService", 
            new ObjectFactory().createGetUser(user),
                    new WebServiceMessageCallback() {
                        public void doWithMessage(WebServiceMessage message) {
                            try {
                                SoapMessage soapMessage = (SoapMessage)message;
                                SoapHeader header = soapMessage.getSoapHeader();
                                StringSource headerSource = new StringSource("<version>1.0</version>");
                                        Transformer transformer = TransformerFactory.newInstance().newTransformer();
                                        transformer.transform(headerSource, header.getResult());
                            } catch (Exception e) {
                                e.printStackTrace();
                            }
                        }
                }) ;
        } catch (IOException e) {
            e.printStackTrace();
        }
        GetUserResponse responseObject = (GetUserResponse)response.getValue();
    User user = responseObject.getReturn();
    }