[英]Update List within Dict values
如何將字典添加到列表中?
例如,我的數據如下:
[{
"data": "11_1",
"invals": [
{
"num1": "1111111",
"ifName": "Vlan1",
"pairs": {
"TYPE": "3",
"IS_TYPE": "level-2",
"IP": "192.168.1.1",
}
}
]
},
{
"data": "11_2",
"invals": [
{
"num1": "2222222",
"ifName": "Vlan2",
"pairs": {
"TYPE": "3",
"IS_TYPE": "level-2",
"IP": "192.168.1.2",
}
}
]
},
{
"data": "11_3",
"invals": [
{
"num1": "33333333",
"ifName": "Vlan3",
"pairs": {
"TYPE": "3",
"IS_TYPE": "level-2",
"IP": "192.168.1.3",
}
}
]
}]
我只想提取數據ifName
和IP
。 在這里我想得到:
[{'int': 'Vlan1', 'address': '192.168.1.1'},{'int': 'Vlan2', 'address': '192.168.1.3'},{'int': 'Vlan3', 'address': '192.168.1.3'}]
碼:
out = [{ 'int': '', 'address': '' }]
for x in output:
for i in x['invals']:
if id == i['num1'] and 'IP' in i['pairs']:
if not i['pairs']['IP'] is '':
out[0]['interface'] = i['ifName']
out[0]['address'] = i['pairs']['IP']
if not i['ifName'] in out[0]['interface']:
out[0]['interface'].update(i['ifName'])
out[0]['address'].update(i['pairs']['IP'])
它已經覆蓋了舊的,無法更新。
使用以下列表理解:
[{'int': d['invals'][0]['ifName'], 'address': d['invals'][0]['pairs']['IP']} for d in l]
輸出:
[{'int': 'Vlan1', 'address': '192.168.1.1'},
{'int': 'Vlan2', 'address': '192.168.1.2'},
{'int': 'Vlan3', 'address': '192.168.1.3'}]
注意:這假定您在列表的每個元素中都保持相同的結構。
您的代碼覆蓋的第一要素out
每一個循環,因為你是指out[0]
各一次。 假設您嘗試獲取具有設置IP的唯一接口的列表,則可能需要使用類似
result = []
saved_interfaces = []
for item in data:
for inval in item['invals']:
if id == i['num1'] and 'IP' in i['pairs']:
if inval['pairs']['IP'] and inval['ifName'] not in saved_interfaces:
result.append({'int':inval['ifName'],'address':inval['pairs']['IP']})
saved_interfaces.append(inval['ifName'])
#print(result)
#[{'int': 'Vlan1', 'address': '192.168.1.1'}, {'int': 'Vlan2', 'address': '192.168.1.2'}, {'int': 'Vlan3', 'address': '192.168.1.3'}]
''
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