[英]How to identify Foreign Keys from sys tables in SQL Server?
我使用以下查詢返回兩個表的主鍵。 是否有類似的方法來查詢外鍵? 我不熟悉創建數據庫,但我沒有看到在 SSMS 的 Object 資源管理器中定義的任何外鍵。 謝謝
select schema_name(tab.schema_id) as [schema_name],
pk.[name] as pk_name,
ic.index_column_id as column_id,
col.[name] as column_name,
tab.[name] as table_name
from sys.tables tab
inner join sys.indexes pk
on tab.object_id = pk.object_id
and pk.is_primary_key = 1
inner join sys.index_columns ic
on ic.object_id = pk.object_id
and ic.index_id = pk.index_id
inner join sys.columns col
on pk.object_id = col.object_id
and col.column_id = ic.column_id
where tab.name = 'custtable' or tab.name = 'custtrans'
order by schema_name(tab.schema_id),
pk.[name],
ic.index_column_id
這是 output,但我需要它來返回這兩個表的外鍵。
schema_name pk_name column_id column_name table_name
dbo I_077ACCOUNTIDX 1 ACCOUNTNUM CUSTTABLE
dbo I_077ACCOUNTIDX 2 DATAAREAID CUSTTABLE
dbo I_077ACCOUNTIDX 3 PARTITION CUSTTABLE
dbo I_078RECID 1 RECID CUSTTRANS
這對你有用嗎? (這通過將多鍵引用顯示為以逗號分隔的列列表來處理多鍵引用,僅供參考):
SELECT fkeys.[name] AS FKName,
OBJECT_NAME(fkeys.parent_object_id) AS TableName,
(SELECT STUFF((SELECT ',' + c.[name]
FROM sys.foreign_keys fk INNER JOIN sys.tables t ON fk.parent_object_id = t.object_id
INNER JOIN sys.columns as c ON t.object_id = c.object_id
INNER JOIN sys.foreign_key_columns AS fc ON c.column_id = fc.parent_column_id
AND fc.constraint_object_id = fk.object_id
AND fc.parent_object_id = fk.parent_object_id
WHERE fk.[name] = fkeys.[name]
FOR XML PATH ('')), 1, 1, '')) AS FKFolumns,
OBJECT_NAME(fkeys.referenced_object_id) AS ReferencedTableName,
(SELECT STUFF((SELECT ',' + c.[name]
FROM sys.foreign_keys fk INNER JOIN sys.tables t ON fk.referenced_object_id = t.object_id
INNER JOIN sys.columns as c ON t.object_id = c.object_id
INNER JOIN sys.foreign_key_columns AS fc ON c.column_id = fc.referenced_column_id
AND fc.constraint_object_id = fk.object_id
AND fc.referenced_object_id = fk.referenced_object_id
WHERE fk.[name] = fkeys.[name]
FOR XML PATH ('')), 1, 1, '')) AS ReferencedFKFolumns
FROM sys.foreign_keys fkeys
ORDER BY FKName;
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