當我嘗試使用函數時，我很困惑 python 中的函數是如何工作的

Question

所以代碼是

magician_names = ['Elon musk', 'Neuralink', 'Neuralink']

def show_magicians(names):
    print("each object/person in the list:\n")
    for name in names:
        print(name.title())

def make_great(list):
    for q in list:
        q = 'the Great ' + q.title()


make_great(magician_names)
print(magician_names)

Answer 1

您只是重新分配循環變量q ，而不是實際改變列表：

def make_great(list):
    for q in list:
        q = 'the Great ' + q.title()  
        # q is now a different new str object, but list is unchanged

改為：

def make_great(lst):  # also do not shadow the built-in list
    for i in range(len(lst)):
        lst[i] = 'the Great ' + lst[i].title()

Answer 2

上面的答案也是正確的，你沒有改變列表我會嘗試澄清一些事情讓我們看看發生了什么看評論

magician_names = ['Elon musk', 'Neuralink', 'Neuralink'] #declared a list

def show_magicians(names): #defined a function though never called
    print("each object/person in the list:\n")
    for name in names:
        print(name.title())

def make_great(list): # defined a function
    for q in list: #iterated on list
        q = 'the Great ' + q.title() # stored a result into memory never used or printed it or returned anything


make_great(magician_names) #called the function operated on list never printed it but it worked in memory
print(magician_names)

簡單來說，如果你在房間里有 Dog Maxi（假設一個函數），除非你打電話給Maxi，否則它不會來找你。 但是 Maxi 將留在房間show_magicians這里。 你打電話給 Maxi，讓他默默地說 woof woof，所以你從來沒有聽到他的聲音，但 Maxi 說並做了他的工作（就像這里沒有打印聲明一樣）。

嘗試放入現實世界的類比希望有所幫助