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[英]How to parse a JSON map in Java or Kotlin where the map has a key
[英]need suggestions about how to parse two values with same key from json format into java map
我正在將 LDAP 中的 ldif 屬性讀取到我的 java 程序中,我最初的想法是將這些屬性放入 map 中,然后從那里解析它們,其中包含我調用的“departmentNumber”屬性,兩個 json 格式值,
departmentNumber: {"sid":"729999","uid":501,"name":"tebase","role":"managers","title":"sales","groups":["others"]}
departmentNumber: {"sid":"724605","uid":37,"name":"tebase","role":"managers","title":"develope","groups":["leaders"]}
所以我用 map 來放它們,一些代碼如下所示,
但我的方法只能檢索第一個 json 值,即包含 {"sid":"729999"} 的值,但沒有包含 {"sid":"724605"} 的第二個值,
我觀察到程序日志是:
2019 22:30:58,237 authentication.mzauth authentication.mzauth.doAuthenticate(mzauth.java:44)
{"uid":"brucelee","mail":"brucelee@gm.macom","displayName":"Bruce Lee","givenName":"Bruce Lee","departmentNumber":"{\"sid\":\"729999\",\"uid\":501,\"name\":\"teabas\",\"role\":\"managers\",\"title\":\"sales\",\"groups\":[\"others\"]}","objectClass":"inetOrgPerson","description":"Bruce Lee","sn":"Bruce Lee","cn":"Z39414","department":"000000","info":"2006/02/12"}
2019 22:30:58,247 services.LdapService services.LdapService.getUser(LdapService.java:251)
ldap user:{"username":"brucelee","fullname":"Bruce Lee","email":"brucelee@gm.macom","departmentid":"729999","titles":[{"schoolid":"729999","titles":["managers","sales"]}],"cloudroles":{"usage":"clouddev","roles":[{"appname":"mail","departmentid":"729999","titles":["managers","sales"]}]},"guid":"c00d5ba660145307c84f2c1e1c557e4ededaf1830029d40aa5b244027","pid":"Z39414","openid":"http://openid.macom/brucelee"}
如您所見,只有 1 個值,即 sid:72999,而不是兩個值,
原來的 ldif 屬性是:
帶有 scope 子樹過濾器的 LDAPv3 基礎:uid=brucelee 請求:ALL
Z39414, Managers, developer.alle.com dn: cn=Z39414,ou=Managers,dc=developer,dc=alle,dc=com uid: brucelee userPassword: qwdmsdierf mail: brucelee@gm.macom info: 2006/02/12 sn:李小龍部門編號:{"sid":"729999","uid":501,"name":"tebase","role":"managers","title":"sales","groups":[ "其他"]} 部門編號:{"sid":"724605","uid":37,"name":"tebase","role":"managers","title":"develope","groups": [“leaders”]} 部門:000000 givenName:李小龍 objectClass:inetOrgPerson objectClass:organizationalPerson objectClass:person objectClass:top cn:Z39414 displayName:李小龍描述:李小龍
搜索結果 search: 2 result: 0 Success numResponses: 2 numEntries: 1
我的問題是,如何將兩個 json 值放入我的 map,或者我對 map 的使用是錯誤的,有更好的方法來處理這種情況?
public DataModel getUser(String uid, String passwd, String role, DataModel user) throws Exception {
private Map<String, String> map = null;
if (role.equals("managers")) {
map = Ldap.getAttrubites(ldapurl, uid, passwd);
List<Titles> titlesArray = new ArrayList<>();
List<Roles> rolesArray = new ArrayList();
map.forEach((key, value)
-> {logger.info("{} - {}", key, value); });
if (key.equals("departmentNumber")) {
List<StringModel> model = map.get("departmentNumber")).get();
model.stream().forEach(k -> {
for (int i = 0; i < model.size(); i++) {
Titles titles = new Titles();
List<String> titleList = new ArrayList<>();
String userid = model.get(i).getUid();
String mtitle = model.get(i).getRole();
String subtitle = model.get(i).getTitle();
titleList.add(mtitle);
titleList.add(subtitle);
titles.setSchoolid(schoolid);
titles.setTitles(titleList);
titlesArray.add(titles);
........ });}
user.setTitles(titlesArray);
.........;
} return user;
}
java.util.Map<K,V>
接口為每個鍵只保存一個值。 如果要為每個鍵保存多個值,則需要為V
部分指定一個集合 class。 例如,像下面這樣。
Map<String, List<String>> map = ...
Java EE API 中定義的javax.ws.rs.core.MultivaluedMap
接口是實現您想要做的事情的示例。
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