如何在 Python 中將字符串轉換為此類列表

Question

我正在使用一個庫，它返回一個 Python 列表。

當我打印該列表時，它看起來像這樣：

print(face_locations)

[(92, 254, 228, 118), (148, 661, 262, 547)]

print(type(face_locations))

<class 'list'>

我有一個帶有值的字符串： "92 254 228 118;148 661 262 547" 。

我想將此字符串轉換為相同的數據類型。

到目前為止我做了什么：

face_locations= "92 254 228 118;148 661 262 547"
face_locations= face_locations.split(";")
for i in range(len(face_locations)):
    face_locations[i] = face_locations[i].split(" ")

兩者都是列表...但是當我稍后在代碼中運行此 function 時，出現錯誤：

for (top, right, bottom, left), face_encoding in zip(face_locations, face_encodings): 
    ....do something

Answer 1

使用列表理解和 map 的元素str到int 。

face_locations= "92 254 228 118;148 661 262 547"
face_locations= face_locations.split(";")
[tuple(map(int, elem.split(' '))) for elem in face_locations]

Output：

[(92, 254, 228, 118), (148, 661, 262, 547)]

Answer 2

beer44 有一個很好的答案，只是為了展示 map 節省了多少工作：

face_locations = "92 254 228 118;148 661 262 547"
face_locations = face_locations.split(";")
face_locations = [face_locations[x].split(' ') for x in range(len(face_locations))]
for sublist in face_locations:
    for i in range(len(sublist)):
        sublist[i] = int(sublist[i])
face_locations = [tuple(sublist) for sublist in face_locations]

Output：

[(92, 254, 228, 118), (148, 661, 262, 547)]