如何檢查一個列表是否包含另一個列表的 2 個元素？

Question

我希望能夠檢查一個列表是否包含另一個列表的 2 個元素（總共有 3 個元素）

例如：

list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if #list2 contains any 2 elements of list1:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")

Answer 1

我將使用以下問題中描述的類似描述，只是這次檢查集合交集的長度： 如何找到列表交集？

list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if len(list(set(a) & set(b))) == 2:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")

Answer 2

您可以編寫一個 function 來檢查兩個列表之間的共同元素，然后驗證該元素的數量是否等於 2。

例如：

def intersection(list1, list2): 
     lst3 = [value for value in list1 if value in list2] 
     return lst3 


list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if len(intersection(list1, list2) == 2):
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")

Answer 3

def my_func(list1, list2):
    count = 0
    for i in list1:
        for j in list2:
            if(i == j) : count += 1
    print(count)
    if(count >= 2) : return True
    else: return False


list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if my_func(list1, list2):#list2 contains any 2 elements of list1:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")

Answer 4

您可以使用itertools.combinations()從list2獲取所有兩個元素的集合，並查看它們是否是list1的子集：

import itertools

if any(set(comb).issubset(set(list1)) for comb in itertools.combinations(list2, 2)):
    print("yes, ...")
...

Answer 5

count = 0
for ele in list2:
    if ele in list1:
        count += 1
if count == 2:
    print ("yes, list 2 contains 2 elements of list 1")
else:
    print ("no, list 2 does not contain 2 elements of list 1")

Answer 6

list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if len(set(list1).intersection(set(list2))) == 2:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")

.intersection 方法接受兩個集合並找出它們之間的共同點。 如果它們之間的共同點是 2 個元素，那么你就有了你想要的。

Answer 7

這有效：

list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]
val = 0
for idx in list1:
    for idx2 in list2:
        if idx == idx2:
            val += 1
if val == 2:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")