如何检查一个列表是否包含另一个列表的 2 个元素？

Question

我希望能够检查一个列表是否包含另一个列表的 2 个元素（总共有 3 个元素）

例如：

list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if #list2 contains any 2 elements of list1:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")

Answer 1

我将使用以下问题中描述的类似描述，只是这次检查集合交集的长度： 如何找到列表交集？

list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if len(list(set(a) & set(b))) == 2:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")

Answer 2

您可以编写一个 function 来检查两个列表之间的共同元素，然后验证该元素的数量是否等于 2。

例如：

def intersection(list1, list2): 
     lst3 = [value for value in list1 if value in list2] 
     return lst3 


list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if len(intersection(list1, list2) == 2):
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")

Answer 3

def my_func(list1, list2):
    count = 0
    for i in list1:
        for j in list2:
            if(i == j) : count += 1
    print(count)
    if(count >= 2) : return True
    else: return False


list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if my_func(list1, list2):#list2 contains any 2 elements of list1:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")

Answer 4

您可以使用itertools.combinations()从list2获取所有两个元素的集合，并查看它们是否是list1的子集：

import itertools

if any(set(comb).issubset(set(list1)) for comb in itertools.combinations(list2, 2)):
    print("yes, ...")
...

Answer 5

count = 0
for ele in list2:
    if ele in list1:
        count += 1
if count == 2:
    print ("yes, list 2 contains 2 elements of list 1")
else:
    print ("no, list 2 does not contain 2 elements of list 1")

Answer 6

list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if len(set(list1).intersection(set(list2))) == 2:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")

.intersection 方法接受两个集合并找出它们之间的共同点。 如果它们之间的共同点是 2 个元素，那么你就有了你想要的。

Answer 7

这有效：

list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]
val = 0
for idx in list1:
    for idx2 in list2:
        if idx == idx2:
            val += 1
if val == 2:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")