[英]Create Dynamic JPA Query
我有一個包含許多字段作為查詢過濾器的視圖,並且我正在使用 JPA 派生查詢,但是為每個字段/過濾器組合創建所有查詢將是乏味且冗長的。
我發現我可以為它創建一個動態查詢,但不確定如何。
到目前為止,我已經在我的存儲庫中創建了這些查詢,但還需要更多:
public interface EmployeeReportInfoViewRepository extends PagingAndSortingRepository<EmployeeReportInfo, Long> {
List<EmployeeReportInfo> findByControlNumber(String controlNmber);
List<EmployeeReportInfo> findByManager(String manager);
List<EmployeeReportInfo> findByofficeLocation(String officeLocation);
List<EmployeeReportInfo> findByBenchFlag(char benchFlag);
List<EmployeeReportInfo> findByBillableFlag(char billableFlag);
List<EmployeeReportInfo> findByEnableFlag(boolean enableFlag);
List<EmployeeReportInfo> findByLastNameAndFirstNameAndControlNumber(String lastName, String firstName,String controlNumber);
List<EmployeeReportInfo> findByLastNameAndFirstNameAndControlNumberAndManager(String lastName, String firstName,String controlNmber,String manager);
List<EmployeeReportInfo> findByLastNameAndFirstNameAndControlNumberAndManagerAndOfficeLocation(String lastName, String firstName,String controlNmber,String manager,String officeLocation);
List<EmployeeReportInfo> findByLastNameAndFirstNameAndControlNumberAndManagerAndOfficeLocationAndBenchFlag(String lastName, String firstName,String controlNmber,String manager,String officeLocation, char benchFlag);
List<EmployeeReportInfo> findByLastNameAndFirstNameAndControlNumberAndManagerAndOfficeLocationAndBenchFlagAndBillableFlag(String lastName, String firstName,String controlNmber,String manager,String officeLocation, char benchFlag,char bllableFlag);
List<EmployeeReportInfo> findByLastNameAndFirstNameAndControlNumberAndManagerAndOfficeLocationAndBenchFlagAndBillableFlagAndEnableFlagAndStartGreaterThanEqualAndEndLessThanEqual
(String lastName, String firstName,String controlNmber,String manager,String officeLocation, char benchFlag,char bllableFlag,
boolean emableFlag, Date start,Date end);
}
@Entity
@Table(name = "employee_report_view")
public class EmployeeReportInfo {
@Id
@Column(name = "employee_id")
private Long id;
private String name;
private Date start;
private Date end;
@Column(name = "control_number")
private String controlNumber;
@Column(name = "enable_flag")
private boolean enableFlag;
@Column(name = "billable_flag")
private char billableFlag;
@Column(name = "bench_flag")
private char benchFlag;
@Column(name = "office_location")
private String officeLocation;
@Column(name = "manager")
private String manager;
/**
* @return the id
*/
public Long getId() {
return id;
}
/**
* @return the name
*/
public String getName() {
return name;
}
/**
* @param name the name to set
*/
public void setName(String name) {
this.name = name;
}
/**
* @param id the id to set
*/
public void setId(Long id) {
this.id = id;
}
/**
* @return the start
*/
public Date getStart() {
return start;
}
/**
* @param start the start to set
*/
public void setStart(Date start) {
this.start = start;
}
/**
* @return the end
*/
public Date getEnd() {
return end;
}
/**
* @param end the end to set
*/
public void setEnd(Date end) {
this.end = end;
}
/**
* @return the controlNumber
*/
public String getControlNumber() {
return controlNumber;
}
/**
* @param controlNumber the controlNumber to set
*/
public void setControlNumber(String controlNumber) {
this.controlNumber = controlNumber;
}
/**
* @return the enableFlag
*/
public boolean isEnableFlag() {
return enableFlag;
}
/**
* @param enableFlag the enableFlag to set
*/
public void setEnableFlag(boolean enableFlag) {
this.enableFlag = enableFlag;
}
/**
* @return the billableFlag
*/
public char getBillableFlag() {
return billableFlag;
}
/**
* @param billableFlag the billableFlag to set
*/
public void setBillableFlag(char billableFlag) {
this.billableFlag = billableFlag;
}
/**
* @return the benchFlag
*/
public char getBenchFlag() {
return benchFlag;
}
/**
* @param benchFlag the benchFlag to set
*/
public void setBenchFlag(char benchFlag) {
this.benchFlag = benchFlag;
}
/**
* @return the officeLocation
*/
public String getOfficeLocation() {
return officeLocation;
}
/**
* @param officeLocation the officeLocation to set
*/
public void setOfficeLocation(String officeLocation) {
this.officeLocation = officeLocation;
}
/**
* @return the manager
*/
public String getManager() {
return manager;
}
/**
* @param manager the manager to set
*/
public void setManager(String manager) {
this.manager = manager;
}
}
您想改為編寫本機 Sql 查詢嗎? 你可以通過 entityManager
我可以理解您的需求:您想根據表單發出的 url 動態生成查詢條件。假設 url 映射到后端到HashMap<String,String>
。
例如,url:
127.0.0.1/employees?nameContains=jack&ageEquals=10
Map:
HashMap<String, String>:key:nameContains,value:jack,key:ageEuqals,value:10
Spring 框架可以自動執行此映射( RequestParamMapMethodArgumentResolver
)。 您需要做的是通過這個 map 動態生成規范( Specification )。
謂詞 like(Expression x, String pattern); => 包含
謂詞等於(表達式 x,表達式 y); => 相等
這是一個比較復雜的解決思路,需要前表組件和后端的協調,但是會很方便。
我說的比較簡單籠統,細節很多(比如嵌套屬性,一對一,一對多等)
另外,你可以看看http://www.querydsl.com/
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