如何將金額、借方、貸方和余額排列在 1 行中

Question

我想將我的查詢安排成單行（每個 cdvno、金額、借方、貸方和余額 1 行）但是我無法安排它們。 成1單行

示例代碼

select a.cdvno,b.Amount, a.debit, a.credit, a.credit + a.debit - coalesce(b.amount,0) as balance
from (
    select cdvno, debit, sum(credit) credit, trantype
    from cdvdtl  
    where debit = 0
    group by cdvno, debit, trantype
    union all
    select cdvno, sum(debit) debit, credit, trantype
    from cdvdtl  
    where credit = 0
    group by cdvno, credit, trantype
) a
left join cdvhdr b
    on b.cdvno = a.cdvno
    and b.trantype = a.trantype
where  a.credit + a.debit - coalesce(b.amount,0) <> 0
order by a.cdvno

結果

cdvno               Amount      debit     credit    balance
000-2016-01000004   25137.50    25326.16    0.00    188.66
000-2016-01000004   25137.50    0.00    25326.16    188.66
000-2016-01000005   15849.90    0.00    16010.00    160.10
000-2016-01000005   15849.90    16010.00    0.00    160.10
000-2016-01000007   217938.73   0.00    220006.50   2067.77
000-2016-01000007   217938.73   220006.50   0.00    2067.77

我試過（總和）金額，但它不起作用。 如果可能的話，我希望結果是這樣的

cdvno             Amount        debit       credit      balance
000-2016-01000004   25137.5     25326.16    25326.16    188.66
000-2016-01000005   15849.9     16010       16010       160.1
000-2016-01000007   217938.73   220006.5    220006.5    2067.77

非常感謝你們，我知道這對你們來說很簡單，但對我來說，我被困在這里：D newbee

Answer 1

您可以忽略union （這會導致為借方和credit創建單獨的條目）並改用select case 。

select a.cdvno,b.Amount
    , a.debit
    , a.credit
    , coalesce(b.amount,0) - coalesce(a.debit, a.credit) as balance
from (
    select cdvno
        , sum(case when credit = 0 then debit else 0 end) as debit
        , sum(case when debit = 0 then credit else 0 end) credit
        , trantype
    from cdvdtl    
    group by cdvno, trantype    
) a 
left join cdvhdr b
     on b.cdvno = a.cdvno and b.trantype = a.trantype
where  a.credit + a.debit - coalesce(b.amount,0) <> 0
    order by a.`cdvno`

Answer 2

我認為你想要聚合條件聚合。 這對我來說很有意義：

select d.cdvno,
       sum(case when d.credit = 0 then d.debit end) as debit,
       sum(case when d.debit = 0 then d.credit end) as credit,
       (h.amount +
        sum(case when d.debit = 0 then d.credit end) -
        sum(case when d.credit = 0 then d.debit end)
       ) as balance
from cdvdtl d join
     cdvhdr h
     on h.cdvno = d.cdvno and h.trantype = d.trantype
group by d.cdvno, h.amount
order by d.cdvno;

注意表別名的使用。 這些不是任意字母，而是表名的縮寫。