[英]$sum from documents and subdocuments group by “$author” (MongoDB)
[英]Mongodb Group and get other fields from documents
更新以便 Mohammad Faisal 擁有最佳解決方案。但是,當添加新文檔時它會中斷,哈哈! 所以我從他的代碼中學到了很多東西並修改了它,它有效! =) 代碼一直在底部。
但這是我說的.. 所以我有這個文件
{"_id":"5ddea2e44eb407059828d740",
"projectname":"wdym",
"username":"easy",
"likes":0,
"link":["ssss"]
}
{"_id":"5ddea2e44eb407059822d740",
"projectname":"thechosenone",
"username":"easy",
"likes":30,
"link":["ssss"]
}
{"_id":"5ddea2e44eb407059828d740",
"projectname":"thanos",
"username":"wiley",
"likes":10,
"link":["ssss"]
}
基本上我想要的是包含最高贊及其相關項目名稱的文檔
例如,輸出將是
"projectname":"thechosenone",
"username":"easy",
"likes":30
}
,
{
"projectname":"thanos",
"username":"wiley",
"likes":10,
}
我的代碼如下
db
.collection("projects")
.aggregate([
{
$group: {
_id: { username: "$username" },
likes: { $max: "$likes" }
}
},
{
$project:{projectname:1}
}
])
$project 給了我一個奇怪的輸出。 但是,沒有 $project 的輸出是正確的。 但我想投射項目名稱、用戶和最高贊。 謝謝你聽我說:)
繼承人的解決方案=)
db
.collection("projects")
.aggregate([
{
$sort: {
likes: -1
}
},
{
$group: {
_id: {
username: "$username"
},
likes: {
$max: "$likes"
},
projectname: {
$push: "$projectname"
},
link: {
$push: "$link"
}
}
},
{
$project: {
username: "$_id.username",
projectname: {
$arrayElemAt: ["$projectname", 0]
},
link: {
$arrayElemAt: ["$link", 0]
}
}
}
])
.toArray()
如果您不必使用 $group 這將解決您的問題:
db.projects.aggregate([
{$sort:{likes:-1}},
{$limit:1}
]).pretty()
結果是
{
"_id" : ObjectId("5ddee7f63cee7cdf247059db"),
"projectname" : "thechosenone",
"username" : "easy",
"likes" : 30,
"links" : ["ssss"]
}
嘗試這個:-
db.collection("projects").aggregate([
{
$group: {
_id: { username: "$username" },
likes: { $max: "$likes" },
projectname: { $push : { $cond: [ { $max: "$likes" }, "$projectname", "" ]}}
}
}
,
{
$project:{
username:"$_id.username",
projectname:{"$reduce": {
"input": "$projectname",
"initialValue": { "$arrayElemAt": ["$projectname", 0] },
"in": { "$cond": [{ "$ne": ["$$this", ""] }, "$$this", "$$value"] }
}},
likes:1
}
}
])
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