使用 C# FileStream 創建 Windows 命名管道

Question

在FileStream類的文檔中， Remarks部分說：

使用 FileStream 類讀取、寫入、打開和關閉文件系統上的文件，以及操作其他與文件相關的操作系統句柄，包括管道、標准輸入和標准輸出。

我知道 System.IO.Pipes 用於在 Windows 中從管道創建、讀取和寫入，但由於我目前正在處理的項目的限制，我無法訪問該包。 似乎 FileStreams 可以與管道進行交互，但我似乎找不到任何有關如何執行此操作的示例。

如何直接使用 FileStream 在 Windows 中通過命名管道執行基本 I/O？

Answer 1

using System;
using System.IO;
using System.Runtime.InteropServices;

namespace Test
{

    class Program
    {
        [DllImport("kernel32.dll", SetLastError = true)]
        static extern IntPtr CreateNamedPipe(string lpName, uint dwOpenMode,
           uint dwPipeMode, uint nMaxInstances, uint nOutBufferSize, uint nInBufferSize,
           uint nDefaultTimeOut, IntPtr lpSecurityAttributes);
        static uint PIPE_ACCESS_DUPLEX = 0x00000003;
        static uint PIPE_ACCESS_INBOUND = 0x00000001;
        static uint PIPE_ACCESS_OUTBOUND = 0x00000002;
        static uint FILE_FLAG_FIRST_PIPE_INSTANCE = 0x00080000;
        static uint FILE_FLAG_WRITE_THROUGH = 0x80000000;
        static uint FILE_FLAG_OVERLAPPED = 0x40000000;
        static uint WRITE_DAC = 0x00040000;
        static uint WRITE_OWNER = 0x00080000;
        static uint ACCESS_SYSTEM_SECURITY = 0x01000000;
        //One of the following type modes can be specified. The same type mode must be specified for each instance of the pipe.
        static uint PIPE_TYPE_BYTE = 0x00000000;
        static uint PIPE_TYPE_MESSAGE = 0x00000004;
        //One of the following read modes can be specified. Different instances of the same pipe can specify different read modes
        static uint PIPE_READMODE_BYTE = 0x00000000;
        static uint PIPE_READMODE_MESSAGE = 0x00000002;
        //One of the following wait modes can be specified. Different instances of the same pipe can specify different wait modes.
        static uint PIPE_WAIT = 0x00000000;
        static uint PIPE_NOWAIT = 0x00000001;
        //One of the following remote-client modes can be specified. Different instances of the same pipe can specify different remote-client modes.
        static uint PIPE_ACCEPT_REMOTE_CLIENTS = 0x00000000;
        static uint PIPE_REJECT_REMOTE_CLIENTS = 0x00000008;


        static void Main(string[] args)
        {

            Console.WriteLine("Hello World!");
            var name = "test";
            var p = CreateNamedPipe(@"\\.\pipe\" + name, PIPE_ACCESS_OUTBOUND, PIPE_TYPE_MESSAGE | PIPE_WAIT, 255, 0, 4096, 0xffffffff, IntPtr.Zero);
            if (p.ToInt32() == -1)
            {
                throw new Exception("Error creating named pipe " + name + " . Internal error: " + Marshal.GetLastWin32Error().ToString());
            }
            var fs = new FileStream(new Microsoft.Win32.SafeHandles.SafeFileHandle(p, true), FileAccess.Write);
            fs.Close();
        }
    }
}

這似乎工作得很好。 比我希望的要丑一點，但並非不可能。 感謝@David Browne 為我指明了正確的方向。

更完整的例子： https : //www.pinvoke.net/default.aspx/kernel32.createnamedpipe