在java.sql.Time中localTime可以連續增加1秒嗎？

Question

在java.time.LocalTime ，有addSeconds()方法。 可以用來連續增加1秒嗎？

LocalTime localTime = Time.valueOf("00:00:00").toLocalTime();
localTime = localTime.plusSeconds(1L);
String output = localTime.toString();
whiteTime = Time.valueOf(output);

我從 Intellij 添加了這部分錯誤消息。

00:00:58
respond to action of white: Black Time
00:00:59
respond to action of white: Black Time
Exception in thread "AWT-EventQueue-0" java.lang.IllegalArgumentException
    at java.sql/java.sql.Time.valueOf(Time.java:109)
    at ui.TimerPanel.blackTimerTikTok(TimerPanel.java:71)
    at util.GameModel$2.actionPerformed(GameModel.java:87)
    at java.desktop/javax.swing.Timer.fireActionPerformed(Timer.java:317)
    at java.desktop/javax.swing.Timer$DoPostEvent.run(Timer.java:249)
    at java.desktop/java.awt.event.InvocationEvent.dispatch(InvocationEvent.java:313)
    at java.desktop/java.awt.EventQueue.dispatchEventImpl(EventQueue.java:770)
    at java.desktop/java.awt.EventQueue$4.run(EventQueue.java:721)
    at java.desktop/java.awt.EventQueue$4.run(EventQueue.java:715)
    at java.base/java.security.AccessController.doPrivileged(AccessController.java:389)
    at java.base/java.security.ProtectionDomain$JavaSecurityAccessImpl.doIntersectionPrivilege(ProtectionDomain.java:85)
    at java.desktop/java.awt.EventQueue.dispatchEvent(EventQueue.java:740)
    at java.desktop/java.awt.EventDispatchThread.pumpOneEventForFilters(EventDispatchThread.java:203)
    at java.desktop/java.awt.EventDispatchThread.pumpEventsForFilter(EventDispatchThread.java:124)
    at java.desktop/java.awt.EventDispatchThread.pumpEventsForHierarchy(EventDispatchThread.java:113)
    at java.desktop/java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:109)
    at java.desktop/java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:101)
    at java.desktop/java.awt.EventDispatchThread.run(EventDispatchThread.java:90)

當它到達00:00:59時，它看起來會出錯。 如何使其00:01:00連續計數秒？

Answer 1

問題是您正在使用java.sql.Time.valueOf(String)並依賴於LocalTime.toString()格式，該格式可能不會打印秒數，因為：

所使用的格式將是輸出完整時間值的最短格式，其中省略部分隱含為零。

您應該使用Time.valueOf(LocalTime) ：

LocalTime localTime = Time.valueOf("00:00:59").toLocalTime();
localTime = localTime.plusSeconds(1);
System.out.println(Time.valueOf(localTime)); // 00:01:00

Answer 2

要添加到什么@Karol Dowbecki回答，如果你需要用你的字符串表示LocalTime ，你可以使用DateTimeFormatter保持一致的格式：

DateTimeFormatter formatter = DateTimeFormatter.ofPattern("HH:mm:ss");

String output = localTime.format(formatter);
whiteTime = Time.valueOf(output);

這將在時間滾動時輸出00:01:00並且不會給您錯誤