[英]Can localTime be added by 1 second continually in java.sql.Time?
在java.time.LocalTime
,有addSeconds()
方法。 可以用来连续增加1秒吗?
LocalTime localTime = Time.valueOf("00:00:00").toLocalTime();
localTime = localTime.plusSeconds(1L);
String output = localTime.toString();
whiteTime = Time.valueOf(output);
我从 Intellij 添加了这部分错误消息。
00:00:58
respond to action of white: Black Time
00:00:59
respond to action of white: Black Time
Exception in thread "AWT-EventQueue-0" java.lang.IllegalArgumentException
at java.sql/java.sql.Time.valueOf(Time.java:109)
at ui.TimerPanel.blackTimerTikTok(TimerPanel.java:71)
at util.GameModel$2.actionPerformed(GameModel.java:87)
at java.desktop/javax.swing.Timer.fireActionPerformed(Timer.java:317)
at java.desktop/javax.swing.Timer$DoPostEvent.run(Timer.java:249)
at java.desktop/java.awt.event.InvocationEvent.dispatch(InvocationEvent.java:313)
at java.desktop/java.awt.EventQueue.dispatchEventImpl(EventQueue.java:770)
at java.desktop/java.awt.EventQueue$4.run(EventQueue.java:721)
at java.desktop/java.awt.EventQueue$4.run(EventQueue.java:715)
at java.base/java.security.AccessController.doPrivileged(AccessController.java:389)
at java.base/java.security.ProtectionDomain$JavaSecurityAccessImpl.doIntersectionPrivilege(ProtectionDomain.java:85)
at java.desktop/java.awt.EventQueue.dispatchEvent(EventQueue.java:740)
at java.desktop/java.awt.EventDispatchThread.pumpOneEventForFilters(EventDispatchThread.java:203)
at java.desktop/java.awt.EventDispatchThread.pumpEventsForFilter(EventDispatchThread.java:124)
at java.desktop/java.awt.EventDispatchThread.pumpEventsForHierarchy(EventDispatchThread.java:113)
at java.desktop/java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:109)
at java.desktop/java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:101)
at java.desktop/java.awt.EventDispatchThread.run(EventDispatchThread.java:90)
当它到达00:00:59
时,它看起来会出错。 如何使其00:01:00
连续计数秒?
问题是您正在使用java.sql.Time.valueOf(String)
并依赖于LocalTime.toString()
格式,该格式可能不会打印秒数,因为:
所使用的格式将是输出完整时间值的最短格式,其中省略部分隐含为零。
您应该使用Time.valueOf(LocalTime)
:
LocalTime localTime = Time.valueOf("00:00:59").toLocalTime();
localTime = localTime.plusSeconds(1);
System.out.println(Time.valueOf(localTime)); // 00:01:00
要添加到什么@Karol Dowbecki回答,如果你需要用你的字符串表示LocalTime
,你可以使用DateTimeFormatter
保持一致的格式:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("HH:mm:ss");
String output = localTime.format(formatter);
whiteTime = Time.valueOf(output);
这将在时间滚动时输出00:01:00
并且不会给您错误
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