[英]How to get data from database as nested JSON array?
我正在嘗試使用 PHP/PDO 從 MySQL 中提取數據並將其格式化為嵌套的 JSON 數組。
這是我得到的:
{
"host1": [
{
"vmnic_name": "vmnic0",
"switch_name": "switch1",
"port_id": "GigabitEthernet1\/0\/1"
},
{
"vmnic_name": "vmnic1",
"switch_name": "switch1",
"port_id": "GigabitEthernet1\/0\/2"
}
],
"host2": {
"2": {
"vmnic_name": "vmnic0",
"switch_name": "switch1",
"port_id": "GigabitEthernet1\/0\/3"
},
"3": {
"vmnic_name": "vmnic1",
"switch_name": "switch1",
"port_id": "GigabitEthernet1\/0\/4"
}
}
}
我想讓它說“host_name”:“host1”等,而不僅僅是“host1”。 並且對於第一個主機之后的主機沒有像第一個主機那樣像“2”或“3”這樣的數字。
這是我的代碼:
$arr = array();
$result = $stmt->fetchAll(PDO::FETCH_ASSOC);
foreach ($result as $key => $item) {
$arr[$item['host_name']][$key] = array(
'vmnic_name'=>$item['vmnic_name'],
'switch_name'=>$item['switch_name'],
'port_id'=>$item['port_id']
);
}
echo json_encode($arr, JSON_PRETTY_PRINT);
如果您只在查詢中選擇這些列,那么就這么簡單:
foreach ($result as $item) {
$arr[$item['host_name']][] = $item;
}
如果出於某種原因必須選擇更多列供以后使用,則只需插入host_name
並刪除$key
作為索引:
foreach ($result as $item) {
$arr[$item['host_name']][] = array(
'host_name'=>$item['host_name'],
'vmnic_name'=>$item['vmnic_name'],
'switch_name'=>$item['switch_name'],
'port_id'=>$item['port_id']
);
}
這很容易。 將其解碼為一個數組,然后將其粘貼到另一個數組中。
$array = json_decode($json, true);
$x = [];
$x['host_name'] = $array;
var_dump(json_encode($x, JSON_PRETTY_PRINT));
這會給你:
string(747) "{ "host_name": { "host1": [ { "vmnic_name": "vmnic0", "switch_name": "switch1", "port_id": "GigabitEthernet1\/0\/1" }, { "vmnic_name": "vmnic1", "switch_name": "switch1", "port_id": "GigabitEthernet1\/0\/2" } ], "host2": { "2": { "vmnic_name": "vmnic0", "switch_name": "switch1", "port_id": "GigabitEthernet1\/0\/3" }, "3": { "vmnic_name": "vmnic1", "switch_name": "switch1", "port_id": "GigabitEthernet1\/0\/4" } } } }"
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