[英]C# JSON Serialize/Deserialize - INPUT problem
我在 JSON 中遇到序列化和反序列化問題我做了 2 個任務來讀取 JSON 文件,如下所示:
[
{
"ID": 1,
"OIB": 123456789,
"ime": "name",
"prezime": "surname",
"grad": "city"
}
]
現在我必須添加另一個 ID 為 2 的客戶端,以及新的用戶信息。 我可以毫無問題地讀取這個 JSON 文件,但我一直堅持寫入同一個文件。
public struct Klijent
{
public int ID { get; set; }
public long OIB { get; set; }
public string ime { get; set; }
public string prezime { get; set; }
public string grad { get; set; }
}
來自 JSON 的“FetchClient”
public static List<Klijent> DohvatiKlijente()
{
List<Klijent> lKlijent = new List<Klijent>();
StreamReader klijent = new StreamReader("x");
string sJson = "";
using (klijent)
{
sJson = klijent.ReadToEnd();
lKlijent = JsonConvert.DeserializeObject<List<Klijent>>(sJson);
}
return lKlijent;
}
“AddClient”到 JSON
OIB -> personal identificator
ID -> should go +1 with every entry of client
grad -> city
ime -> name
prezime -> surname
public static void DodavanjeKlijenata()
{
Console.Write("Unesite OIB klijenta: ");
string pOIB = Console.ReadLine();
long nullOIB = 0;
long.TryParse(pOIB, out nullOIB);
int id = 0;
Console.Write("Unesite ime klijenta: ");
string ime1 = Console.ReadLine();
Console.Write("Unesite prezime klijenta: ");
string prezime1 = Console.ReadLine();
Console.Write("Unesite grad klijenta: ");
string grad1 = Console.ReadLine();
List<Klijent> lKlijent = DohvatiKlijente();
foreach (var Klijent in lKlijent)
{
id = Klijent.ID + 1;
}
Klijent dKlijent = new Klijent()
{
ID = id,
OIB = nullOIB,
ime = ime1,
prezime = prezime1,
grad = grad1
};
var serializer = new JsonSerializer();
using (var sw = new StreamWriter("x"))
using (JsonWriter writer = new JsonTextWriter(sw))
{
serializer.Serialize(writer, dKlijent);
}
}
這段代碼確實有效,但似乎每次我的 JSON 文件都會被刪除,而且它的格式只有一行,我想把它分成多行。
謝謝 :)
這里有兩件事你需要做
確保將新客戶附加到現有列表中
為此,您可以將新客戶端添加到列表中
lKlijent.Add(dKlijent);
現在你需要序列化 List,而不是lKlijent
using (JsonWriter writer = new JsonTextWriter(sw))
{
serializer.Serialize(writer, lKlijent);
}
格式化
對於格式化,您可以使用格式化設置。 例如,
var serializer = new JsonSerializer() { Formatting = Formatting.Indented} ;
附加評論
1. ID的計算
不是使用以下循環計算新 ID,
foreach (var Klijent in lKlijent)
{
id = Klijent.ID + 1;
}
您可以使用Enumerable.Last()
獲取列表中的最后一個客戶端。 例如,
var id = lKlijent?.Any()!=true? 0:lKlijent.Last().ID;
2. 重寫 DohvatiKlijente 方法
DohvatiKlijente
方法可以重寫為
public static List<Klijent> DohvatiKlijente()
{
return JsonConvert.DeserializeObject<List<Klijent>>(File.ReadAllText("C:\\Users\\Hrvoje\\Desktop\\Polica Osiguranja MAIN\\Polica Osiguranja\\klijent.json"));
}
同樣,寫回文件可以簡化為
var jsonString = JsonConvert.SerializeObject(lKlijent,Newtonsoft.Json.Formatting.Indented);
File.WriteAllText(outputFilePath,jsonString);
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