[英]Customize table name of hyperjaxb3 generated entity?
我有一個XML模式,其中具有的simpleType(diagnosisCode)如下所示:
<xsd:complexType name="MedicalClaimDetail">
<xsd:element name="diagnosisCode" minOccurs="1" maxOccurs="99">
<xsd:simpleType>
<xsd:restriction base="xsd:string">
<xsd:minLength value="1"/>
<xsd:maxLength value="30"/>
</xsd:restriction>
</xsd:simpleType>
</xsd:element>
</xsd:complexType>
這生成了一個與子類具有一對多關系的頂級類,如下所示:
具有原始屬性的父類和 hyperjaxb 生成的類的瞬態屬性:
@Entity(name = "MedicalClaimDetail")
@Table(name = "A_ES_MED_CLM_DETAIL")
@Inheritance(strategy = InheritanceType.JOINED)
public class MedicalClaimDetail
implements Serializable, Equals, HashCode
{
private final static long serialVersionUID = 1L;
@XmlElement(required = true)
protected List<String> diagnosisCode;
protected transient List<MedicalClaimDetailDiagnosisCodeItem> diagnosisCodeItems;
@Transient
public List<String> getDiagnosisCode() {
if (diagnosisCode == null) {
diagnosisCode = new ArrayList<String>();
}
return this.diagnosisCode;
}
public void setDiagnosisCode(List<String> diagnosisCode) {
this.diagnosisCode = diagnosisCode;
}
@OneToMany(targetEntity = MedicalClaimDetailDiagnosisCodeItem.class, cascade = {
CascadeType.ALL
})
@JoinColumn(name = "DIAGNOSISCODEITEMS_MEDICALCL_0")
public List<MedicalClaimDetailDiagnosisCodeItem> getDiagnosisCodeItems() {
if (this.diagnosisCodeItems == null) {
this.diagnosisCodeItems = new ArrayList<MedicalClaimDetailDiagnosisCodeItem>();
}
if (ItemUtils.shouldBeWrapped(this.diagnosisCode)) {
this.diagnosisCode = ItemUtils.wrap(this.diagnosisCode, this.diagnosisCodeItems, MedicalClaimDetailDiagnosisCodeItem.class);
}
return this.diagnosisCodeItems;
}
public void setDiagnosisCodeItems(List<MedicalClaimDetailDiagnosisCodeItem> value) {
this.diagnosisCode = null;
this.diagnosisCodeItems = null;
this.diagnosisCodeItems = value;
if (this.diagnosisCodeItems == null) {
this.diagnosisCodeItems = new ArrayList<MedicalClaimDetailDiagnosisCodeItem>();
}
if (ItemUtils.shouldBeWrapped(this.diagnosisCode)) {
this.diagnosisCode = ItemUtils.wrap(this.diagnosisCode, this.diagnosisCodeItems, MedicalClaimDetailDiagnosisCodeItem.class);
}
}
子類為:
@XmlAccessorType(XmlAccessType.FIELD)
@Entity(name = "MedicalClaimDetailDiagnosisCodeItem")
@Table(name = "MEDICALCLAIMDETAILDIAGNOSISC_0")
@Inheritance(strategy = InheritanceType.JOINED)
public class MedicalClaimDetailDiagnosisCodeItem
implements Serializable, Item<String>
{
private final static long serialVersionUID = 1L;
@XmlElement(name = "diagnosisCode", namespace = "http://vo.edge.fm.cms.hhs.gov")
protected String item;
@XmlTransient
protected Long hjid;
@Basic
@Column(name = "ITEM", length = 30)
public String getItem() {
return item;
}
public void setItem(String value) {
this.item = value;
}
@Id
@Column(name = "HJID")
@GeneratedValue(strategy = GenerationType.AUTO)
public Long getHjid() {
return hjid;
}
public void setHjid(Long value) {
this.hjid = value;
}
}
現在的問題是:有沒有辦法自定義自動生成實體的表名: MedicalClaimDetailDiagnosisCodeItem ,它是 hyperjaxb 生成的表名作為 MEDICALCLAIMDETAILDIAGNOSISC_0
我們怎樣才能做到這一點?
我解決了這個問題。 請參閱下面的代碼以使用外部綁定自定義生成的實體/類的表名:
<jaxb:bindings
schemaLocation="xsd/medicalClaim/MedicalClaimDetail.xsd"
node="/xs:schema">
<jaxb:bindings
node="xs:complexType[@name='MedicalClaimDetail']//xs:element[@name='diagnosisCode']">
<hj:generated-class
className="MedicalClaimDetailDiagnosisCodeItem">
<hj:entity>
<orm:table name="A_ES_MED_CLM_DTL_DG_CD_ITM" />
</hj:entity>
</hj:generated-class>
</jaxb:bindings>
</jaxb:bindings>
HJ3 有很多自定義選項。
例如,請參見以下項目:
https://github.com/highsource/hyperjaxb3/tree/master/ejb/tests/cu-one/src/main/resources
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