[英]How do we convert a Python dictionary to a .txt file (with a format)?
[英]How to convert a txt file with dictionary format to dataframe in python?
我有一個包含數據的文件,例如,
{"cid": "ABCD", "text": "alphabets", "time": "1 week", "author": "xyz"}
{"cid": "EFGH", "text": "verb", "time": "2 week", "author": "aaa"}
{"cid": "IJKL", "text": "noun", "time": "3 days", "author": "nop"}
我希望讀取這個文件並創建一個數據框,例如,
cid text time author
ABCD alpha 1week xyz
EFGH verb 2week aaa
IJKL noun 3days nop
您可以嘗試使用不同的分隔符將文件讀取為 csv 並獲取第一列,然后應用ast.literal_eval
轉換為實際字典並轉換回數據幀:
import ast
output = pd.DataFrame(pd.read_csv('file.txt',sep='|',header=None).iloc[:,0]
.apply(ast.literal_eval).tolist())
print(output)
cid text time author
0 ABCD alphabets 1 week xyz
1 EFGH verb 2 week aaa
2 IJKL noun 3 days nop
工作示例:
file = """{"cid": "ABCD", "text": "alphabets", "time": "1 week", "author":"xyz"}
{"cid": "EFGH", "text": "verb", "time": "2 week", "author": "aaa"}
{"cid": "IJKL", "text": "noun", "time": "3 days", "author": "nop"}"""
import io #dont need for reading a file directly , just for example
import ast
print(pd.DataFrame(pd.read_csv(io.StringIO(file),sep='|',header=None).iloc[:,0]
.apply(ast.literal_eval).tolist()))
cid text time author
0 ABCD alphabets 1 week xyz
1 EFGH verb 2 week aaa
2 IJKL noun 3 days nop
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