用於計算總計的 SQL 查詢

Question

我對 SQL 查詢很陌生，所以如果我到目前為止所做的事情真的很奇怪，請對我放輕松:)

我有兩個表 - A 表示收入，B 表示支出：

Business_ID Income_Desc Income_Amount
1           Income A    1000
1           Income B    3000
1           Income C    2000

Business_ID Expen_Amount
1           2500

我想制作一個表格，顯示每個收入金額，一個支出金額，總收入，總支出和總收入-總支出的總計。

如果可能的話像這樣

Business_ID Income Description  Income Amount   Expenditure Amount  Total
1           Income A            1000            2500                 -
1           Income B            3000            -                    -
1           Income C            2000            -                    -
1           All Amounts         6000            2500                  3500

這是我迄今為止嘗試過的

SELECT a. Business_ID, COALESCE (a.Income_Desc, 'All Amounts') AS 'Income Description', SUM(a.Income_Amount) AS 'Income Amount', SUM(b.Expen_Amount) AS Expenditure Amount', (sum(a.Income_Amount)-SUM(b.Expen_Amount)) AS 'Total'
FROM Income AS a LEFT JOIN Expenditure AS b ON a.Business_ID = b. Business_ID
GROUP BY a. Business_ID,  a.Income_Desc WITH ROLLUP

我得到的結果是這樣的

Business_ID Income Description  Income Amount   Expenditure Amount  Total
1           Income A            1000            2500                 -1500
1           Income B            3000            2500                 500
1           Income C            2000            2500                 -500
1           All Amounts         6000            7500                 -1500
            All Amounts         6000            7500                 -1500

是否有可能獲得像我上面提供的那樣的輸出？ 你能告訴我如何實現它（或非常接近的東西）嗎？

謝謝

Answer 1

您可以使用row_number()進行join ：

with ie as (
      select i.business_id, i.income_desc, i.income_amount,
             e.expen_amount
      from (select i.*,
                   row_number() over (partition by business_id order by income_desc) as seqnum
            from income i
           ) i left join
           (select e.*,
                   row_number() over (partition by business_id order by expen_amount) as seqnum
            from expenditure e
           ) e
           on i.business_id = e.business_id and i.seqnum = e.seqnum
       )
select ie.*
from ie
union all
select business_id, 'Total', sum(income_amount), sum(expen_amount)
from ie
group by business_id;

Answer 2

您可以從原始查詢中創建子查詢，並且只選擇業務 ID 不為空的值。 此外，使用CASE WHEN來標識那些小於 0 的值並將其替換為“-”：

SELECT x.Business_ID
     , x.`Income Description`
     , x.`Income Amount`
     , x.`Expenditure Amount`
     , x.Total
FROM
(SELECT a. Business_ID
     , COALESCE (a.Income_Desc, 'All Amounts') AS 'Income Description'
     , SUM(a.Income_Amount) AS 'Income Amount'
     , SUM(b.Expen_Amount) AS 'Expenditure Amount'
     , CASE WHEN (sum(a.Income_Amount)-SUM(b.Expen_Amount)) < 0
       THEN '-'
       ELSE (sum(a.Income_Amount)-SUM(b.Expen_Amount))
       END AS 'Total'
FROM Income AS a 
    LEFT JOIN Expenditure AS b ON a.Business_ID = b.Business_ID
WHERE a.Business_ID is not null and b.Business_ID is not null
GROUP BY a.Business_ID, a.Income_Desc WITH ROLLUP) as x
where x.Business_ID is not null

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