[英]sql query with totals in the same query
select
grade, pro_abo as procUpper, pro_with as procMiddle,
pro_below as procLower, pro_insuf as procNa,
cum_abo as cumulativeUpper, cum_with as cumulativeMiddle,
cum_below as cumulativeLower, cum_insuf as cumulativeNa
from
(select distinct v.*
from M_VW v, m_info mi
where v.id = mi.id and mi.id_ti = 1094574915) ;
此查詢的輸出是
Grade procUpper procMiddle procLower procNa cumulativeUpper cumulativeMiddle cumulativeLower cumulativeNa
HOD 100 100 100 4 100 100 100 10
lecturer 100 100 100 10 100 100 100 10
Professor 100 100 100 10 100 100 100 10
RA 100 100 100 10 100 100 100 10
PA 100 100 100 4 100 100 100 10
我想在底部添加總計,例如,
Grade procUpper procMiddle procLower procNa cumulativeUpper cumulativeMiddle cumulativeLower cumulativeNa
HOD 100 100 100 4 100 100 100 10
lecturer 100 100 100 10 100 100 100 10
Professor 100 100 100 10 100 100 100 10
RA 100 100 100 10 100 100 100 10
PA 100 100 100 4 100 100 100 10
Total 100% 100% 100% 38 100% 100% 100% 50
第 5 列和最后一列不必有 %。
在這種情況下,最簡單的方法可能是:
with t as (
select grade, pro_abo as procUpper, pro_with as procMiddle, pro_below as procLower,
pro_insuf as procNa, cum_abo as cumulativeUpper, cum_with as cumulativeMiddle, cum_below as cumulativeLower,
cum_insuf as cumulativeNa
from (select distinct v.*
from M_VW v join
m_info mi
where v.id = mi.id and mi.id_ti = 1094574915
) v
)
select t.*
from t
union all
select NULL, sum(pro_abo), sum(pro_with), sum(pro_below), sum(pro_insuf), sum(cum_abo), sum(cum_with), sum(cum_below)
from t
order by grade nulls last;
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