C# 復雜類構造函數

Question

我有以下系統：一個名為DataClass的“母”類，具有屬性，其中兩個是類， PartClass和MemberClass 。 特別是， MemberClass具有屬性，其中之一是類SideClass - 具有自己的屬性。

這是代碼示例：

using System;

namespace ConsoleApp
{
    public class DataClass
    {
        public int num { get; set; }
        public string code { get; set; }
        public PartClass part { get; set; }
        public MemberClass member { get; set; }

        public DataClass()
        {
            PartClass part = new PartClass();
            MemberClass member = new MemberClass();
        }
    }

    public class PartClass
    {
        public int seriesNum { get; set; }
        public string seriesCode { get; set; }

        public PartClass() { }
    }

    public class MemberClass
    {
        public int versionNum { get; set; }
        public SideClass side { get; set; }

        public MemberClass()
        {
            SideClass side = new SideClass();
        }
    }

    public class SideClass
    {
        public string firstDetail { get; set; }
        public string secondDetail { get; set; }
        public bool include { get; set; }

        public SideClass() { }
    }

現在，我正在嘗試初始化DataClass並將值分配給所有屬性，但這不起作用。 因此， DataClass “擁有” PartClass和MemberClass ，而MemberClass本身“看到” SideClass ，它是底層類並且與所有類無關。 這里剩下的代碼：

class Program
{

    static void Main(string[] args)
    {
    DataClass myData = new DataClass()
    {
        num = 13,
        code = "message",
        //from here downwards nothing works; error..
        part.seriesNum = 1,
        part.seriesCode = 7,
        member.versionNum = 9,
        member.side.firstDetail = "pass",
        member.side.secondDetail = "checked",
        member.side.include = true;
    }
}

}

我認為通過安裝構造函數和屬性， DataClass實例化不會有問題，但實際上DataClass沒有看到任何非平凡的屬性（屬性指的是類）。 有人可以幫我嗎？ 謝謝..

Answer 1

使用以下：

DataClass myData = new DataClass()
{
    num = 13,
    code = "message",
    part = new PartClass()
    {
        seriesNum = 1,
        //here down nothing works; error
        seriesCode = "abc"
    },
    member = new MemberClass()
    {
        versionNum = 9,
        side = new Side()
        {
            firstDetail = "pass",
            secondDetail = "checked",
            include = true
        }
    }
};

Answer 2

為了不必每次都手動創建 Member Class 和 Part Class 的實例，您可以使用 get 和 set 方法創建實例。

public class DataClass
{
    public int num { get; set; }
    public string code { get; set; }

    private PartClass _part;
    public PartClass part { get { if (_part == null) _part = new PartClass(); return _part; } set { _part = value; } }


    private MemberClass _member;
    public MemberClass member { get { if (_member == null) _member = new MemberClass(); return _member; } set { _member = value; } }

}

Answer 3

您應該創建一個 DataClass 實例然后初始化字段

DataClass myData = new DataClass();

myData.num = 13,
myData.code = "message",
myData.part.seriesNum = 1,
myData.part.seriesCode = 7,
myData.member.versionNum = 9,
myData.member.side.firstDetail = "pass",
myData.member.side.secondDetail = "checked",
myData.member.side.include = true;