[英]Print out the result of sqlite database query with a format
我有這個學生數據庫有四列: first_name, middle_name, last_name, school, birth_year
。 我已經使用 SELECT 語句成功讀取了 db 的內容,但這里是我陷入困境的地方:
如何使用如下格式打印查詢結果: first_name middle_name(if available) last_name was born in birth_year
? 因此,對於查詢中的每一行,預期的結果都應該這樣做: Aida Blue was born in 1985
。
現在,如果我運行print(all_rows)
代碼將打印這樣的查詢結果: [{'first_name':'Aida', 'middle_name': None, 'last_name': 'Blue', 'school': 'Washington', 'birth_year': 1981}, {...}, ....]
以下是我對此類問題的代碼嘗試:
db = cs.SQL("sqlite:///students.db")
if __name__ == '__main__':
if len(sys.argv) != 2:
print("Usage: python student_school.py school")
sys.exit()
else:
school = str(sys.argv[1])
all_rows = db.execute("SELECT * FROM students WHERE school=?", school)
first = all_rows[:][0] #I want to pick up the first col
middle = all_rows[:][1] #if value <> None?
last= all_rows[:][2]
birth_year = all_rows[:][4]
print(first_name, " " , middle_name, " ", last_name, "was born in ", birth_year \n)
任何人都可以請教嗎? 謝謝!
all_rows
變量字典列表。 每個字典代表一個學生記錄。
(單個空間)。 沒有必要明確寫出" "
。 與\\n
相同,無需顯式編寫 '\\n'。 在此處閱讀更多信息https://docs.python.org/3/library/functions.html#print 。db = cs.SQL("sqlite:///students.db")
if __name__ == '__main__':
if len(sys.argv) != 2:
print("Usage: python student_school.py school")
sys.exit()
else:
school = str(sys.argv[1])
all_rows = db.execute("SELECT * FROM students WHERE school=?", school)
for student in all_rows:
print(student['first_name'], student['middle_name'] if student['middle_name'] else '', student['last_name'], "was born in", student['birth_year'])
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.