[英]Print out the result of sqlite database query with a format
我有这个学生数据库有四列: first_name, middle_name, last_name, school, birth_year
。 我已经使用 SELECT 语句成功读取了 db 的内容,但这里是我陷入困境的地方:
如何使用如下格式打印查询结果: first_name middle_name(if available) last_name was born in birth_year
? 因此,对于查询中的每一行,预期的结果都应该这样做: Aida Blue was born in 1985
。
现在,如果我运行print(all_rows)
代码将打印这样的查询结果: [{'first_name':'Aida', 'middle_name': None, 'last_name': 'Blue', 'school': 'Washington', 'birth_year': 1981}, {...}, ....]
以下是我对此类问题的代码尝试:
db = cs.SQL("sqlite:///students.db")
if __name__ == '__main__':
if len(sys.argv) != 2:
print("Usage: python student_school.py school")
sys.exit()
else:
school = str(sys.argv[1])
all_rows = db.execute("SELECT * FROM students WHERE school=?", school)
first = all_rows[:][0] #I want to pick up the first col
middle = all_rows[:][1] #if value <> None?
last= all_rows[:][2]
birth_year = all_rows[:][4]
print(first_name, " " , middle_name, " ", last_name, "was born in ", birth_year \n)
任何人都可以请教吗? 谢谢!
all_rows
变量字典列表。 每个字典代表一个学生记录。
(单个空间)。 没有必要明确写出" "
。 与\\n
相同,无需显式编写 '\\n'。 在此处阅读更多信息https://docs.python.org/3/library/functions.html#print 。db = cs.SQL("sqlite:///students.db")
if __name__ == '__main__':
if len(sys.argv) != 2:
print("Usage: python student_school.py school")
sys.exit()
else:
school = str(sys.argv[1])
all_rows = db.execute("SELECT * FROM students WHERE school=?", school)
for student in all_rows:
print(student['first_name'], student['middle_name'] if student['middle_name'] else '', student['last_name'], "was born in", student['birth_year'])
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