在列表理解中使用 while 循環和 for 循環

Question

l1=[1,2,3,4,5,6,7]
l2=[1, 4, 9, 16, 25, 36, 49]
l3=[]
new_list=[]
i=1
while i<8:
    for num in l2:
        l3.append(num*i)
        i+=1
new_list.append(l3)
print(new_list)

如何將其轉換為列表理解？

    new_list=[new_list.append(num*i) while(i<8) for num in l2 i+=1]

預期輸出：

 new_list = [1, 8, 27, 64, 125, 216, 343]

Answer 1

這樣做：

l1=[1,2,3,4,5,6,7]
l2=[1, 4, 9, 16, 25, 36, 49]
new_list = [i*j for i,j in zip(l1, l2)]
print(new_list)

輸出

[1, 8, 27, 64, 125, 216, 343]

Answer 2

您可以使用列表理解和zip ：

[i*n for i, n in zip(range(1,8), l2)]

或者itertools.starmap和operator.mul :(不要忘記導入它們）

list(starmap(mul, zip(range(1,8), l2)))

兩者都會產生相同的輸出：

from itertools import groupby, starmap, product
from operator import itemgetter, mul

l1 = range(1,8)
l2=[1, 4, 9, 16, 25, 36, 49]

new_list1 = [i*n for i, n in zip(l1, l2)]
new_list2 = list(starmap(mul, zip(l1, l2)))

print(new_list1)
print(new_list2)

---

結果：

[1, 8, 27, 64, 125, 216, 343]
[1, 8, 27, 64, 125, 216, 343]