返回包含字母的單詞列表

Question

我想返回一個包含字母的單詞列表，不考慮大小寫。 假設我有sentence = "Anyone who has never made a mistake has never tried anything new" ，那么f(sentence, a)將返回

['Anyone', 'has', 'made', 'a', 'mistake', 'has', 'anything']

這就是我所擁有的

import re 
def f(string, match):
    string_list = string.split()
    match_list = []
    for word in string_list:

        if match in word:
            match_list.append(word)
    return match_list

Answer 1

你不需要re 。 使用str.casefold ：

[w for w in sentence.split() if "a" in w.casefold()]

輸出：

['Anyone', 'has', 'made', 'a', 'mistake', 'has', 'anything']

Answer 2

如果沒有標點符號，您可以使用字符串拆分。

match_list = [s for s in sentence.split(' ') if 'a' in s.lower()]

Answer 3

這是另一個變化：

sentence = 'Anyone who has never made a mistake has never tried anything new'

def f (string, match) :
    match_list = []
    for word in string.split () :
        if match in word.lower ():
            match_list.append (word)
    return match_list

print (f (sentence, 'a'))