返回包含字母的单词列表

Question

I wanna return a list of words containing a letter disregarding its case. Say if i have sentence = "Anyone who has never made a mistake has never tried anything new" , then f(sentence, a) would return

['Anyone', 'has', 'made', 'a', 'mistake', 'has', 'anything']

This is what i have

import re 
def f(string, match):
    string_list = string.split()
    match_list = []
    for word in string_list:

        if match in word:
            match_list.append(word)
    return match_list

Answer 1

You don't need re . Use str.casefold :

[w for w in sentence.split() if "a" in w.casefold()]

Output:

['Anyone', 'has', 'made', 'a', 'mistake', 'has', 'anything']

Answer 2

如果没有标点符号，您可以使用字符串拆分。

match_list = [s for s in sentence.split(' ') if 'a' in s.lower()]

Answer 3

Here's another variation :

sentence = 'Anyone who has never made a mistake has never tried anything new'

def f (string, match) :
    match_list = []
    for word in string.split () :
        if match in word.lower ():
            match_list.append (word)
    return match_list

print (f (sentence, 'a'))