[英]IP Blacklist lookup with PHP
我正在嘗試計算 IP 在數組函數“dnsblookup”中出現的點擊次數。 如果IP出現3次,則應echo "3|10",其中10為數組中黑名單數據庫的總數。 我的代碼為每個 IP 返回“1|10”,即使它在數組的黑名單數據庫中出現不止一次。 我不知道我在哪里犯了錯誤。 我需要幫助來完成這個項目。 謝謝你。 我在遇到問題的確切代碼之前放置了多個星號 (*)。
<?php
function dnsbllookup($ip)
{
$dnsbl_lookup = array (
"dnsbl-1.uceprotect.net","all.s5h.net","wormrbl.imp.ch",
"dnsbl-2.uceprotect.net","blacklist.woody.ch",
"dnsbl-3.uceprotect.net","combined.abuse.ch","dnsbl.spfbl.net",
"dnsbl.dronebl.org","http.dnsbl.sorbs.net");
$list = "";
if ($ip) {
$reverse_ip = implode(".", array_reverse(explode(".", $ip)));
foreach ($dnsbl_lookup as $host) {
if (checkdnsrr($reverse_ip . "." . $host . ".", "A")) {
$list .= implode(".", array_reverse(explode(".",$reverse_ip))) . ' <font color="red">
<strong>is Listed in </strong></font>'. $host . '<br />';
}
}
}
if (empty($list)) {
echo 'No record was not found in the IP blacklist database for: '.$ip;
echo $list;
echo "<br>";
echo "0";
echo "|";
echo count($dnsbl_lookup);
********************
} else {
$list1 = explode(" ", $list);
echo ($list);
echo "<br>";
echo "Blacklisted: ".count($list1);
echo "|";
echo count($dnsbl_lookup);
}
}
您應該降低復雜性並使用字符串插值以便於閱讀和調試。
function dnsbllookup($ip)
{
$dnsbl_lookup =
[
'dnsbl-1.uceprotect.net', 'all.s5h.net', 'wormrbl.imp.ch',
'dnsbl-2.uceprotect.net', 'blacklist.woody.ch',
'dnsbl-3.uceprotect.net', 'combined.abuse.ch', 'dnsbl.spfbl.net',
'dnsbl.dronebl.org', 'http.dnsbl.sorbs.net'
];
$dns_count = count($dnsbl_lookup);
$list = [];
if ($ip)
{
$reverse_ip = implode(".", array_reverse(explode(".", $ip)));
foreach ($dnsbl_lookup as $host)
if (checkdnsrr("$reverse_ip.$host.", "A"))
$list[] = "$ip <font color=\"red\"><strong>is Listed in </strong></font> $host<br />\n";
}
$list_count = count($list);
if (0 === $list_count)
echo "No record was not found in the IP blacklist database for: $ip<br>\n";
else
{
$list_str = implode(" ", $list);
echo "$list_str<br>\nBlacklisted: $list_count<br>\n";
}
echo "$list_count|$dns_count\n";
}
dnsbllookup('54.201.153.20'); // 3 entries
dnsbllookup('185.12.225.17'); // 1 entry
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.