[英]How do I select a trigonal sector of a hexagonal Brillouin zone in python?
[英]How do I find the last sector of harddisk?
我沒有嘗試通過將扇區數乘以 10 來找到最后一個扇區。我嘗試通過增加 1 來找到它,但系統很累,花了很多時間。 我不想過濾掉就緒命令的輸出。
如何找到柱面、磁頭和扇區的數量。 我想我會通過從 chs 系統轉換為 lba 系統來獲得扇區數。
import os
def main():
s=1
if os.name == "nt":
while True:
if read_sector(r"\\.\physicaldrive0",s)=='':
break
else:
s=s*10
print(s)
else:
while True:
if read_sector("/dev/sda",s)=='':
break
else:
s=s*10
print(s)
def read_sector(disk, sector_no=0):
f = open(disk, 'rb')
f.seek(sector_no * 1)
read = f.read(1)
return read
if __name__ == "__main__":
main()
或者
import os
def main():
s=0
if os.name == "nt":
while True:
if read_sector(r"\\.\physicaldrive0",s)=='':
break
else:
s=s+1
print(s)
else:
while True:
if read_sector("/dev/sda",s)=='':
break
else:
s=s+1
print(s)
def read_sector(disk, sector_no=0):
f = open(disk, 'rb')
f.seek(sector_no * 1)
read = f.read(1)
return read
if __name__ == "__main__":
main()
import os
def end_sector(disk):
os.system("fdisk -l %s >fdisk.lst"%disk)
with open("fdisk.lst") as file:
dosya=file.read()
dosya=dosya.split()
j=0
for i in dosya:
j=j+1
for i in range(j):
if dosya[i]=="sektör":
max_sector=int(dosya[i-1])
for i in range(j):
if dosya[i]=="=" and dosya[i-1]==dosya[i+1]:
sector_size=int(dosya[i+1])
return max_sector,sector_size
dizi=end_sector("/dev/sdb")
print(dizi)
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