[英]How to break this while(true) loop?
嗨,我試圖打破這個循環並在兩個 if 語句都為真時返回坐標。 然而,循環永遠不會結束。 我該如何解決?
public static String[] positionQuery(int dim, Scanner test_in) {
Scanner scanner = new Scanner(System.in);
System.out.println("Provide origin and destination coordinates.");
System.out.println("Enter two positions between A1-H8:");
while(true) {
String line = scanner.nextLine();
String[] coordinates = line.split(" ");
if(coordinates.length == 2) {
String origin = coordinates[0];
String dest = coordinates[1];
if(validCoordinate(origin, dim) && validCoordinate(dest,dim)) {
return coordinates;
}
}
System.out.println("ERROR: Please enter valid coordinate pair separated by space.");
}
}
我想我對 validCoordinates 有問題,因為我只對 validCoordinates 進行了驗證,但找不到我做錯了什么。
public static boolean validCoordinate(String coordinate, int dimension) {
boolean isValidCoordinate;
String [] alphabet = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
int [] numbers = new int [dimension];
int one = 1;
for(int i = 0; i < dimension; i++){
numbers[i] = one + i;
}
for(int i = 0; i < dimension; i++){
if((Character.toString(coordinate.charAt(0))).contains(alphabet[i])) {
for(int j = 0; j < dimension; j++) {
if ((coordinate.substring(1)).contains(Integer.toString(numbers[j]))) {
return true;
}
}
}
}
return false;
}
嗨,我試圖打破這個循環,當兩個if語句都為true時返回坐標。 但是,循環永遠不會結束。 我該如何解決?
public static String[] positionQuery(int dim, Scanner test_in) {
Scanner scanner = new Scanner(System.in);
System.out.println("Provide origin and destination coordinates.");
System.out.println("Enter two positions between A1-H8:");
while(true) {
String line = scanner.nextLine();
String[] coordinates = line.split(" ");
if(coordinates.length == 2) {
String origin = coordinates[0];
String dest = coordinates[1];
if(validCoordinate(origin, dim) && validCoordinate(dest,dim)) {
return coordinates;
}
}
System.out.println("ERROR: Please enter valid coordinate pair separated by space.");
}
}
我想我對validCoordinates有問題,因為我只是對validCoordinates有所了解,但找不到我做錯了什么。
public static boolean validCoordinate(String coordinate, int dimension) {
boolean isValidCoordinate;
String [] alphabet = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
int [] numbers = new int [dimension];
int one = 1;
for(int i = 0; i < dimension; i++){
numbers[i] = one + i;
}
for(int i = 0; i < dimension; i++){
if((Character.toString(coordinate.charAt(0))).contains(alphabet[i])) {
for(int j = 0; j < dimension; j++) {
if ((coordinate.substring(1)).contains(Integer.toString(numbers[j]))) {
return true;
}
}
}
}
return false;
}
您的有效坐標不正確,它只檢查由字母數組中的維度參數指定的前幾個值。
嘗試這個
public static boolean validCoordinate(String coordinate, int dimension) {
boolean isValidCoordinate;
String [] alphabet = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
int [] numbers = new int [dimension];
for(int i = 0; i < dimension; i++){
numbers[i] = 1 + i;
}
if(Arrays.asList(alphabet).contains(Character.toString(coordinate.charAt(0)))) {
for(int j = 0; j < dimension; j++) {
if ((coordinate.substring(1)).contains(Integer.toString(numbers[j]))) {
return true;
}
}
}
return false;
}
您絕對可以改進此代碼,我會將其作為挑戰留給您。
這是相關的 repl https://repl.it/@Blakeinstein/question60251495
忍者編輯:我建議你修改你的位置查詢
public static String[] positionQuery(int dim) {
Scanner scanner = new Scanner(System.in);
System.out.println("Provide origin and destination coordinates.");
System.out.println("Enter two positions between A1-H8:");
while(true) {
String line = scanner.nextLine();
String[] coordinates = line.split(" ");
if(coordinates.length == 2) {
String origin = coordinates[0];
String dest = coordinates[1];
if(validCoordinate(origin, dim) && validCoordinate(dest,dim)) {
return coordinates;
}
else{
System.out.println("Coordinates are not valid");
}
}
else{
System.out.println("ERROR: Please enter valid coordinate pair separated by space.");
}
}
}
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