使用while循環計算用戶輸入的數量

Question

我嘗試創建一個 while 循環函數，其中程序采用浮點數（米）形式的六個單獨的用戶輸入。 如果數字大於零，則接受每個輸入。 如果數字小於零，則取消每個輸入。

While 循環應該計算最多六個用戶輸入，然后打印：

• 成功輸入數
• 被駁回的輸入數量
• 最大的輸入是
• 所有輸入的平均值是

我的挑戰是我不明白如何使用 while 循環，以便它計數到一定數量的輸入，然后停止

以下是示例輸出：

Give the latest user input: 86.2
Give the latest user input: 81.2
Give the latest user input:  79.6
Give the latest user input:  89.3
Give the latest user input:  -1
Give the latest user input:  86.5

There were 5 succesful input(s).
There were 1 dismissed input(s).
The highest input was 89.3.
The mean of all inputs was 84.56 meters.

Answer 1

怎么樣：

nums = []
while len(nums)<6:
  n = int(input())
  if n > 0:
    nums.append(n)

print(nums)
print(min(nums))
print(max(nums))

給予：

[2, 2, 3, 4, 1, 4]
1
4

Answer 2

嘗試

sum=0
count=0
good_count=0
max_val=-1
while count<6:
    number = int(input())
    if number > 0:
        sum=sum + number
        good_count=good_count+1
        if number>max_val:
            max_val=number            
    count=count + 1
print('there were {0} valid inputs'.format(good_count))
print('there were {0} invalid inputs'.format(count-good_count))

if good_count>0:
    print('the average value was '  ,sum/good_count)
    print('the maximum input values was ', max_val)
else:
    print('there were no valid inputs so an average cannot be calculated')
    print('there were no valid inputs so a maximum value does not exist')```