使用while循环计算用户输入的数量

Question

我尝试创建一个 while 循环函数，其中程序采用浮点数（米）形式的六个单独的用户输入。 如果数字大于零，则接受每个输入。 如果数字小于零，则取消每个输入。

While 循环应该计算最多六个用户输入，然后打印：

• 成功输入数
• 被驳回的输入数量
• 最大的输入是
• 所有输入的平均值是

我的挑战是我不明白如何使用 while 循环，以便它计数到一定数量的输入，然后停止

以下是示例输出：

Give the latest user input: 86.2
Give the latest user input: 81.2
Give the latest user input:  79.6
Give the latest user input:  89.3
Give the latest user input:  -1
Give the latest user input:  86.5

There were 5 succesful input(s).
There were 1 dismissed input(s).
The highest input was 89.3.
The mean of all inputs was 84.56 meters.

Answer 1

怎么样：

nums = []
while len(nums)<6:
  n = int(input())
  if n > 0:
    nums.append(n)

print(nums)
print(min(nums))
print(max(nums))

给予：

[2, 2, 3, 4, 1, 4]
1
4

Answer 2

尝试

sum=0
count=0
good_count=0
max_val=-1
while count<6:
    number = int(input())
    if number > 0:
        sum=sum + number
        good_count=good_count+1
        if number>max_val:
            max_val=number            
    count=count + 1
print('there were {0} valid inputs'.format(good_count))
print('there were {0} invalid inputs'.format(count-good_count))

if good_count>0:
    print('the average value was '  ,sum/good_count)
    print('the maximum input values was ', max_val)
else:
    print('there were no valid inputs so an average cannot be calculated')
    print('there were no valid inputs so a maximum value does not exist')```