[英]transmute over all columns : removing comma and every characters after comma
我想在所有列的字符串中刪除逗號和逗號后的每個字符
from <- c("UK, port unspecified", "Nantes", "London", "America", "La Martinique, port unspecified")
to <- c("Benin", "Widha", "France, *", "America, Port unspecified", "London")
network <- data.frame(from, to)
我的 df :
from to
1 UK, port unspecified Benin
2 Nantes Widha
3 London France, *
4 America America, Port unspecified
5 La Martinique, port unspecified London
我想要的是 :
from to
1 UK Benin
2 Nantes Widha
3 London France
4 America America
5 La Martinique London
我可以結合transmute_all
(或transmute_if
)(包dplyr)和split
(包tidyr)功能dplyr管?
您可以使用mutate_all
/ transmute_all
並使用逗號后刪除所有sub
。
library(dplyr)
network %>% mutate_all(~sub(",.*", "", .))
# from to
#1 UK Benin
#2 Nantes Widha
#3 London France
#4 America America
#5 La Martinique London
或者在帶有lapply
基礎 R 中。
df[] <- lapply(network, function(x) sub(",.*", "", x))
數據
使用stringsAsFactors = FALSE
數據作為字符讀取。
network <- data.frame(from, to, stringsAsFactors = FALSE)
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