[英]how to (crud) insert select update delete on mysql 5.7 json column
[英]How to delete keys in JSON column of MySQL
我的數據很臟,現在我正在嘗試糾正它們。
數據是這樣的:
mysql> select attrs from goods limit 10;
+--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| attrs |
+--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| {"logo": "1", "cover": "", "level": 0, "tag_6": 8, "summary": "L1", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1532572800000, "courseStartTime": 1531706400000} |
| {"logo": "1", "cover": "", "level": 0, "tag_6": 8, "summary": "L1", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1533717600000, "courseStartTime": 1532851200000} |
| {"logo": "1", "cover": "", "level": 0, "tag_6": 8, "summary": "L1", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1534851600000, "courseStartTime": 1533985200000} |
| {"logo": "1", "cover": "", "level": 0, "tag_6": 8, "summary": "L2", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1532594400000, "courseStartTime": 1531728000000} |
| {"logo": "1", "cover": "", "level": 0, "tag_147": 8, "tag_145": 2 "summary": "L2", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1533728400000, "courseStartTime": 1532862000000} |
| {"logo": "1", "cover": "", "level": 0, "tag_6": 8, "summary": "L2", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1534819200000, "courseStartTime": 1533952800000} |
| {"logo": "1", "cover": "", "level": 0, "tag_127": 8, "summary": "NGL", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1532605200000, "courseStartTime": 1531738800000} |
| {"logo": "1", "cover": "", "level": 0, "tag_6": 8, "summary": "NGL", "showStatus": 0, "classAmount": 0, "productType": 0, "courseEndTime": 1533696000000, "courseStartTime": 1532829600000} |
|
+--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
如果這些對中的任何一個存在(key, value)
我想刪除列attrs
中的一些(key, value)
對。 例如tag_147
和tag_124
是臟的,那么任何命中對都將被刪除。
{"tag_147": 1, "tag_124": 2} ===> {}
{"tag_147": 1 "tag_100":2} ==> {"tag_100": 2}
我怎樣才能實現它? 謝謝。
我嘗試過的是 1. 找到包含鍵tag_147
和tag_124
attrs
。 2. 然后更新 attrs。 我原來的 Sql 是這樣的:
update goods
set json_remove(*XXX*)
where (select json_keys(attrs) from goods ) contains (*tag_147*, *tag_127*)
在這里,我被構造contains
語句阻止了......
如果你只是想刪除來自這兩個標簽attrs
同時包含他們的價值觀,你可以使用JSON_REMOVE
任何attrs
通過發現價值JSON_CONTAINS_PATH
,使用all
的模式JSON_CONTAINS_PATH
只找到其中包含這兩個標簽值:
UPDATE goods
SET attrs = JSON_REMOVE(attrs, '$.tag_147', '$.tag_124')
WHERE JSON_CONTAINS_PATH(attrs, 'all', '$.tag_147', '$.tag_124')
如果要完全刪除attrs
值包含兩個標簽的行,可以在DELETE
查詢中使用相同的JSON_CONTAINS_PATH
條件:
DELETE
FROM goods
WHERE JSON_CONTAINS_PATH(attrs, 'all', '$.tag_147', '$.tag_124')
如果您想從包含其中任何一個的attrs
值中刪除這些標簽,您可以刪除UPDATE
中的WHERE
子句,即
UPDATE goods
SET attrs = JSON_REMOVE(attrs, '$.tag_147', '$.tag_145')
要刪除attrs
值包含任何標簽的行,請將all
參數更改為JSON_CONTAINS_PATH
為one
:
DELETE
FROM goods
WHERE JSON_CONTAINS_PATH(attrs, 'one', '$.tag_147', '$.tag_145')
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.