刪除列表列表列表中“”中的空格

Question

results = [[['2020 is the year', '29 year old "Samuel G"', '25 year old "John P Krul"', '40 year old "Trey Nunez S"', '22 year old "Fiona S Paul"', '50 year old "Sean J Beal"']]]

我嘗試跟隨，但這似乎擺脫了python3中“”中的中間詞。

print([re.sub(r'"(\w+)(\s(\w+))*"', '"\\1\\3"', x.lower()) for x in results[0]])

我想要的輸出是

results = [[['2020 is the year', '29 year old "samuelg"', '25 year old "johnpkrul"', '40 year old "treynunezs"', '22 year old "fionaspaul"', '50 year old "seanjbeal"']]]

僅在“”和“”中的小寫字母之間刪除，以便“John P Krul”變為“johnpkrul”，同時保持所有內容相同。

代碼需要改什么？

Answer 1

你可以試試這個。

def f(x): #Takes re.match object as input
    a=x.group() #extractting the match
    return a.replace(' ','').lower() #them to lower and removing spaces

[re.sub(r'\"([^"]*)\"',f,i) for i in results]

---

['2020 is the year',
 '29 year old "samuelg"',
 '25 year old "johnpkrul"',
 '40 year old "treynunezs"',
 '22 year old "fionaspaul"',
 '50 year old "seanjbeal"']

編輯：對於列表列表

[[[re.sub(r'\"([^"]*)\"',f,i) for i in lst2] for lst2 in lst1] for lst1 in results]

輸出：

[[['2020 is the year',
   '29 year old "samuelg"',
   '25 year old "johnpkrul"',
   '40 year old "treynunezs"',
   '22 year old "fionaspaul"',
   '50 year old "seanjbeal"']]]