[英]Remove spaces in " " in List of list of list
results = [[['2020 is the year', '29 year old "Samuel G"', '25 year old "John P Krul"', '40 year old "Trey Nunez S"', '22 year old "Fiona S Paul"', '50 year old "Sean J Beal"']]]
我尝试跟随,但这似乎摆脱了python3中“”中的中间词。
print([re.sub(r'"(\w+)(\s(\w+))*"', '"\\1\\3"', x.lower()) for x in results[0]])
我想要的输出是
results = [[['2020 is the year', '29 year old "samuelg"', '25 year old "johnpkrul"', '40 year old "treynunezs"', '22 year old "fionaspaul"', '50 year old "seanjbeal"']]]
仅在“”和“”中的小写字母之间删除,以便“John P Krul”变为“johnpkrul”,同时保持所有内容相同。
代码需要改什么?
你可以试试这个。
def f(x): #Takes re.match object as input
a=x.group() #extractting the match
return a.replace(' ','').lower() #them to lower and removing spaces
[re.sub(r'\"([^"]*)\"',f,i) for i in results]
['2020 is the year',
'29 year old "samuelg"',
'25 year old "johnpkrul"',
'40 year old "treynunezs"',
'22 year old "fionaspaul"',
'50 year old "seanjbeal"']
编辑:对于列表列表
[[[re.sub(r'\"([^"]*)\"',f,i) for i in lst2] for lst2 in lst1] for lst1 in results]
输出:
[[['2020 is the year',
'29 year old "samuelg"',
'25 year old "johnpkrul"',
'40 year old "treynunezs"',
'22 year old "fionaspaul"',
'50 year old "seanjbeal"']]]
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