[英]PL SQL Loop Table after insert and update
我正在嘗試在插入到名為約會的不同表后循環遍歷名為 broker 的表,並更新 broker 表上的值,這是我擁有的。 當我嘗試創建觸發器時,它會出現一個錯誤,提示“觸發器創建時有編譯錯誤”
CREATE OR REPLACE TRIGGER broker_level_trigger
AFTER INSERT ON appointment
DECLARE
counter integer := 1;
BEGIN
for o in (SELECT * FROM broker)
loop
SELECT COUNT(appointment.broker_id) INTO app_number FROM appointment INNER JOIN broker ON broker.broker_id = appointment.broker_id WHERE broker.broker_id = counter;
IF app_number > 15 THEN
UPDATE broker SET broker_level = 'gold' WHERE broker_id = counter;
counter := counter + 1;
end loop;
end;
/
經紀人表有一個名為 broker_level 的字段,它根據約會而改變,如果約會上的 broker_id 字段超過 15,我希望它改變
show err
是一件美妙的事情。 (我創建了您使用的虛擬表)。
SQL> CREATE OR REPLACE TRIGGER broker_level_trigger
2 AFTER INSERT ON appointment
3 DECLARE
4 counter integer := 1;
5 BEGIN
6 for o in (SELECT * FROM broker)
7 loop
8 SELECT COUNT(appointment.broker_id)
9 INTO app_number
10 FROM appointment INNER JOIN broker
11 ON broker.broker_id = appointment.broker_id
12 WHERE broker.broker_id = counter;
13
14 IF app_number > 15 THEN
15 UPDATE broker SET
16 broker_level = 'gold'
17 WHERE broker_id = counter;
18 counter := counter + 1;
19
20 end loop;
21 end;
22 /
Warning: Trigger created with compilation errors.
SQL> show err
Errors for TRIGGER BROKER_LEVEL_TRIGGER:
LINE/COL ERROR
-------- -----------------------------------------------------------------
18/7 PLS-00103: Encountered the symbol "LOOP" when expecting one of
the following:
if
如果你仔細觀察,你會發現IF
錯過了它的END IF
。 讓我們添加它:
SQL> CREATE OR REPLACE TRIGGER broker_level_trigger
2 AFTER INSERT ON appointment
3 DECLARE
4 counter integer := 1;
5 BEGIN
6 for o in (SELECT * FROM broker)
7 loop
8 SELECT COUNT(appointment.broker_id)
9 INTO app_number
10 FROM appointment INNER JOIN broker
11 ON broker.broker_id = appointment.broker_id
12 WHERE broker.broker_id = counter;
13
14 IF app_number > 15 THEN
15 UPDATE broker SET
16 broker_level = 'gold'
17 WHERE broker_id = counter;
18 counter := counter + 1;
19 END IF; --> missing
20 end loop;
21 end;
22 /
Warning: Trigger created with compilation errors.
SQL> show err
Errors for TRIGGER BROKER_LEVEL_TRIGGER:
LINE/COL ERROR
-------- -----------------------------------------------------------------
6/5 PL/SQL: SQL Statement ignored
7/12 PLS-00201: identifier 'APP_NUMBER' must be declared
8/7 PL/SQL: ORA-00904: : invalid identifier
12/5 PL/SQL: Statement ignored
12/8 PLS-00201: identifier 'APP_NUMBER' must be declared
現在缺少APP_NUMBER
; 你使用它,但從未聲明它。 讓我們現在就開始做吧:
SQL> CREATE OR REPLACE TRIGGER broker_level_trigger
2 AFTER INSERT ON appointment
3 DECLARE
4 counter integer := 1;
5 app_number number; --> missing
6 BEGIN
7 for o in (SELECT * FROM broker)
8 loop
9 SELECT COUNT(appointment.broker_id)
10 INTO app_number
11 FROM appointment INNER JOIN broker
12 ON broker.broker_id = appointment.broker_id
13 WHERE broker.broker_id = counter;
14
15 IF app_number > 15 THEN
16 UPDATE broker SET
17 broker_level = 'gold'
18 WHERE broker_id = counter;
19 counter := counter + 1;
20 END IF; --> missing
21 end loop;
22 end;
23 /
Trigger created.
SQL>
就是這樣。
如果您不使用 SQL*Plus 而是使用其他一些工具,您可以隨時查詢user_errors
:
Warning: Trigger created with compilation errors.
SQL> select line, position, text from user_errors where name = 'BROKER_LEVEL_TRIGGER' order by sequence;
LINE POSITION TEXT
----- --------- ------------------------------------------------------------
8 12 PLS-00201: identifier 'APP_NUMBER' must be declared
9 7 PL/SQL: ORA-00904: : invalid identifier
7 5 PL/SQL: SQL Statement ignored
13 8 PLS-00201: identifier 'APP_NUMBER' must be declared
13 5 PL/SQL: Statement ignored
SQL>
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.