[英]How to create a file with '01' if name exists?
open() 內置 function 中是否有特定參數,以便如果文件名已經存在,它會通過在文件名中添加數字來創建文件?
這樣如果“file.txt”存在,它會自動創建“file-01.txt”
或任何其他解決方案。!
不,我不認為有這樣的事情,但你可以使用os.path.isfile
自己做:
import os
filename = "yourFileName.txt"
if os.path.isfile(filename): #check if filename exists in the directory
filename = filename.split(".")[:-1] + "-01" + filename.split(".")[-1]
with open(filename, "w+") as f:
f.write(yourString)
像這樣的東西?
import os
if os.path.exists(filename):
fileparts = filename.split('.')
filename = fileparts[0] + '01.'
for a in fileparts[1:]:
filename += a
我找到了解決辦法,謝謝!!
b = True
c = 1
while b:
f_name = 'Task-{:02.0f}.txt'.format(c)
try:
f = open(f_name,'x')
b = False
except FileExistsError:
c += 1
f.close()
看看你對此有何看法。 ...這就是我用來做你正在尋找的東西。 這是我之前發現的解決問題的最小方法,並且很容易包裝成 function:
import os
name = 'blah.txt'
uniq_name = name
while os.path.isfile(uniq_name):
# if increment variable 'delta' isn't defined, make it 1. Otherwise increment
delta = delta+1 if 'delta' in vars() else 1
uniq_name = f'{os.path.splitext(name)[0]}-{delta}{os.path.splitext(name)[1]}'
# this you don't need - it's just equivalent to a 'touch' command to show
# the output
open(uniq_name, 'a').close()
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