如何在 Flutter 的 Shared Preferences 中獲取和設置兩種不同數據類型的值？

Question

我有一個名為cardDetails的 map，其詳細信息是從 Firestore 中獲取的。 獲取數據后，我想使用shared_preferences通過將 map 轉換為字符串並將密鑰設置為 true 來在本地保存詳細信息。 當用戶再次打開應用程序時，我檢查是否已使用getBool(key)讀取該值，然后使用getString(key)從字符串中獲取數據。

問題是 getString(key) 返回 bool 值而不是字符串，因此我無法再次將字符串解碼為 map

════════ Exception caught by widgets library ═══════════════════════════════════════════════════════
The following assertion was thrown building:
type 'bool' is not a subtype of type 'String'

聲明和初始化

Map<String, dynamic> cardDetails;
  var keys;
  bool _initialSharedValue;

  @override
  void initState() {
    super.initState();

    SharedPreferences.getInstance().then((SharedPreferences sp) {
      sharedPreferences = sp;
      _initialSharedValue = sharedPreferences.getBool("homepage");
      // will be null if never previously saved
      if (_initialSharedValue == null) {
        _initialSharedValue = false;
        persist(_initialSharedValue); // set an initial value
      }
      setState(() {});
    });
  }

  Future<void> persist(bool value) async {
    setState(() {
      _initialSharedValue = value;
    });
    await sharedPreferences?.setBool("homepage", value);
  }

  storeCardInSharedPreference(Map cardDetails) async {
    await sharedPreferences?.setString("homepage", json.encode(cardDetails));
  }

在用於構建卡片的 UI 中

    if (sharedPreferences.getBool("homepage"))
      ListView.builder(
        itemBuilder: (context, index) {
          cardDetails = json.decode(sharedPreferences.getString("homepage"));
          return HomepageCards(
            user: widget.user,
            cardDetails: cardDetails[cardDetails.keys.toList()[index]],
          );
        },
        itemCount: 3,
        scrollDirection: Axis.vertical,
        controller: _controller,
        shrinkWrap: true,
      )
    else
      StreamBuilder<DocumentSnapshot>(
        stream: Firestore()
            .collection('homepage')
            .document(widget.user.uid)
            .collection('h')
            .document('28032020')
            .snapshots(),
        builder: (context, snapshot) {
          if (snapshot.data != null) {
            cardDetails = {};
            snapshot.data.data.forEach((index, individualDetail) {
              cardDetails[index] = individualDetail;
            });
            storeCardInSharedPreference(cardDetails);
            sharedPreferences.setBool("homepage", true);
            keys = snapshot.data.data.keys;
          } else {
            // TODO: Convert it to Shimmer with card skeletal layout
            CircularProgressIndicator();
          }

          return ListView.builder(
            itemBuilder: (context, index) {
              return HomepageCards(
                user: widget.user,
                cardDetails:
                    cardDetails[cardDetails.keys.toList()[index]],
              );
            },
            itemCount: keys.length,
            scrollDirection: Axis.vertical,
            controller: _controller,
            shrinkWrap: true,
          );
        },
      )

Answer 1

我通過使用解決了這個問題? 在 if 條件中使其成為可識別 null 的方法調用。

if (sharedPreferences?.getBool("homepage"))